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Stels [109]
3 years ago
8

A student solves the following equation and determines that the solution is −2. is the student correct? explain. 3 a 2 − 6a a2 −

4 = 1 a − 2
Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

Step-by-step explanation:

Solving the equation, it is found that it has no solutions, thus, the student is not correct.

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What is the approximate area of the shaded region under the standard normal curve below? Use the portion of the standard normal
kotegsom [21]

This region as the same area as the one in your previous question.

Pr[1 < <em>Z</em> < 2] = Pr[-2 < <em>Z</em> < -1] ≈ 0.14

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3 years ago
The area of the square at right is 36. what is the value of x<br> a) 6<br> b) 2<br> C) 9<br> d) 4
Rasek [7]
It would be answer a)6
7 0
3 years ago
Read 2 more answers
What is the correct answer?
Alchen [17]
(2,16) hope that helps
5 0
4 years ago
Phyllis invested $11,500, a portion earning a simple interest rate of
Cerrena [4.2K]

Answer:

He invested $8500 with rate 3 1/5%

He invested $3000 with rate 3%

Step-by-step explanation:

* <em>Lets revise the rule of the simple interest</em>

- Simple interest I = PRT, where P in the money invested, R is the

 interest rate and T is the time of investment

- Phyllis invested $11,500

- A portion earning a simple interest rate of 3 1/5% (3.2%) per year

- The rest earning a rate of 3% per year

- After one year the total interest earned on these investments

 was $362.00

- We need to find the amount of money invested in each rate

* Assume that he invested $x with rate 3 1/5% and $y with rate 3%

∵ He invested $11,500 in both rates

∴ x + y = 11,500 ⇒ (1)

∵ He invested $x with 3 1/5%

∵ P = $x

∵ R = 3.2/100 = 0.032

∵ T = 1

∴ I_{1}=x(0.032)(1)

∴ I_{1}=0.032x

∵ He invested $y with 3%

∵ P = $y

∵ R = 3/100 = 0.03

∵ T = 1

∴ I_{2}=y(0.03)(1)

∴ I_{2}=0.03y

∵ The total interest was $362.00

- The total interest = I_{1} + I_{2}

∴ 0.032x + 0.03y = 362.00 ⇒ (2)

<em>We have system of equations</em>

x + y = 11,500 ⇒ (1)

0.032x + 0.03y = 362.00 ⇒ (2)

Multiply equation (1) by -0.03 to eliminate y

-0.03x - 0.03y = 345 ⇒ (3)

Add equations (2) and (3)

0.002x = 17

Divide both sides by 0.002

x = 8500

Substitute the value of x in equation (1)

8500 + y = 11,500

Subtract 8500 from both sides

y = 3000

* He invested $8500 with rate 3 1/5%

* He invested $3000 with rate 3%

7 0
3 years ago
Im legit stuck on this question someone please help me. Q: Anthony purchased 7 5/12 (its written as a fraction btw) pounds of gr
Sedbober [7]

Answer:

4 1/6 or 4 2/12 pounds

Step-by-step explanation:

8 0
3 years ago
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