Answer:
Horizontal asymptote of the graph of the function f(x) = 25/1+4x is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0. There is also a <em>vertical</em> asymptote at x=-1/4
When denominator's degree (1) is higher than nominator's degree (0) then the horizontal asymptote is y=0
Answer:
$286
Step-by-step explanation:
220:100=2.2
2.2 x 30 = 66
220+66=286
X - 1 2/3 = -2
x - 1 2/3 + 1 2/3 = -2 + 1 2/3
x = -1/3