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mariarad [96]
2 years ago
8

What is the area of this figure? ​

Mathematics
1 answer:
polet [3.4K]2 years ago
4 0
First, calculate the area of the square, which is 25

next, find the area of one half of the triangle by multiplying 2.5 and 4 (10), then dividing that by 2 (5).

since the two half’s of the triangle are symmetrical, just add 5 and 5 to get 10.

add the area of the triangle (10) and the square (25) to get the total area.

the answer should be 35

hope this helps!
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If a hexagon is worth 5 and a triangle is worth 3, what is a circle
Olegator [25]

Answer:

6

Step-by-step explanation:

Call pentagon p, circle c and triangle t

We have 2c + 2p = 2p + 2t + c

p = 5, t = 3 so

2c + 2(5) = 2(5) + 2(3) + c

2c + 10 = 10 + 6 + c

2c = 6 + c

c = 6

4 0
3 years ago
Read 2 more answers
Ok y’all help ʜᴇʟᴘᴘᴘᴘᴘ ndjd d dndkdjdjdkdnfn dkcn
umka21 [38]

Answer:

C, 108 ft²

Step-by-step explanation:

To solve, we need to find the area of each of the shapes and then add them together.

The top rectangle's area: 8 * 3 = 24

The left triangle: 3 * 4 * 0.5 = 6

The middle rectangle: 8 * 4 = 32

The right triangle: 4 * 3 * 0.5 = 6

The bottom rectangle: 5 * 8 = 40

Add them all together.

24 + 6 + 32 + 6 + 40 = 108 ft²

Thus, the answer is C, 108 ft²

8 0
3 years ago
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I need these all written out on how they're done along with the answer please
taurus [48]
Well, these are quite simple really, especially 1,2,3 and 4. If you read the questions carefully, you can understand it well. You don’t need to know the answer, you just need to understand
8 0
3 years ago
A pet store can put no more then 5 fish in each tank. What is the least number of tanks the store needs to hold 354 fish?
Vlada [557]
70.8 fish tanks. Because you have to divide 354 by 5.
8 0
3 years ago
If sin a= 12/13 and tan B 8/15 and angles a and b are in qundrant 1 find the value of tan (a+b)
natali 33 [55]

Answer:

The value of Tan (a + b) is \frac{-220}{21} .

Step-by-step explanation:

Given as :

Tan b = \frac{8}{15}

Sin a = \frac{12}{13}

∵Sin Ф = \dfrac{\textrm perpendicular}{\textrm Hypotenuse}

So,  \dfrac{\textrm perpendicular}{\textrm Hypotenuse} =  \frac{12}{13}

Now, Base² = Hypotenuse² -  Perpendicular²

Or, Base² = 13² - 12²

Or,  Base² = 169 - 144

Or,  Base² = 25

∴     Base = \sqrt{25} = 5

And Tan Ф =  \dfrac{\textrm perpendicular}{\textrm Base}

Or, Tan a = \frac{12}{5}

Now, Tan (a + b) = \dfrac{Tan a + Tan b}{1- Tan a Tanb}

Or, Tan (a + b) = \frac{\frac{12}{5}+\frac{8}{5}}{1-(\frac{12}{5}\times \frac{8}{15})}

or, Tan (a + b) = \frac{\frac{36+8}{15}}{\frac{75-96}{75}}

or, Tan (a + b) =\frac{\frac{44}{15}}{\frac{-21}{75}}

Or, Tan (a + b) = \frac{-220}{21}

Hence The value of Tan (a + b) is \frac{-220}{21} . Answer

5 0
3 years ago
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