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2 years ago

What is the area of this figure?

Mathematics

1 answer:

polet [3.4K]2 years ago

4 0

First, calculate the area of the square, which is 25

next, find the area of one half of the triangle by multiplying 2.5 and 4 (10), then dividing that by 2 (5).

since the two half’s of the triangle are symmetrical, just add 5 and 5 to get 10.

add the area of the triangle (10) and the square (25) to get the total area.

the answer should be 35

hope this helps!

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Solve the equation and show all work. 4|x + 1/3| = 20 i'm kind of stuck hhh

34kurt

Absolute value is a function that takes some number and outputs the size of that number, regardless of the sign. By definition, $|x|=x$ if $x\ge0$ , and $|x|=-x$ if $x$ .

For example,

|2| = 2 because the input 2 is positive, so the input is unchanged;
|-3| = -(-3) = 3 because the input -3 is negative, so the sign is switched.

What this means for this problem is that there are two cases to consider:

If $x+\frac13\ge0$ , then $\left|x+\frac13\right|=x+\frac13$ , so that

$4\left(x+\dfrac13\right)=20\implies x+\dfrac13=5\implies\boxed{x=\dfrac{14}3}$

On the other hand, if $x+\frac13$ , then $\left|x+\frac13\right|=-\left(x+\frac13\right)$ , so

$-4\left(x+\dfrac13\right)=20\implies x+\dfrac13=-5\implies\boxed{x=-\dfrac{16}3}$

6 0

4 years ago

Find the complement of 73°

Nimfa-mama [501]

Answer:

18°

Step-by-step explanation:

90-72= 18

The complement of 73 is the angle that when added to 73 forms a right angle which is 90° xd

5 0

3 years ago

Find symmetric equations for the line of intersection of the planes. z = 4x − y − 13, z = 6x + 5y − 13

MArishka [77]

The intersection line of two planes is the cross product of the normal vectors of the two planes.

p1: z=4x-y-13 => 4x-y-z=13
p2: z=6x+5y-13 => 6x+5y-z=13
The corresponding normal vectors are:
n1=<4,-1,-1>
n2=<6,5,-1>

The direction vector of the intersection line is the cross product of the two normals,
vl=
i j k
4 -1 -1
6 5 -1
=<1+5, -6+4, 20+6>
=<6,-2,26>
We simplify the vector by reducing its length by half, i.e.
vl=<3,-1,13>

To find the equation of the line, we need to find a point on the intersection line.
Equate z: 4x-y-13=6x+5y-13 => 2x+6y=0 => x+3y=0.
If x=0, then y=0, z=-13 => line passes through (0,0,-13)

Proceed to find the equation of the line:
L: (0,0,-13)+t(3,-1,13)
Convert to symmetric form:
$\frac{x-0}{3}=\frac{y-0}{-1}=\frac{z-(-13)}{13}$
=>
$\frac{x}{3}=\frac{-y}{1}=\frac{z+13}{13}$

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3 years ago

The base unit used to measure volume/liquid capacity in the metric system is _______.

s2008m [1.1K]

Answer:

Liter

Step-by-step explanation:

Metric system is often used as the primary scheme of measurement in various countries, and is also used as one of the two schemes prevalent in the United States.

The basic units in this scheme of measurement include units such as,

-Meter for measuring length

-Kilogram for measuring mass

-Second for measuring time

The base unit for measuring the liquid capacity, which is more commonly referred to as volume, is liters.

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4 years ago

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Answer:

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3 years ago

What is the area of this figure? ​

What is the area of this figure?