Step-by-step explanation:
it is option c. you interchange the value with y and take inverse.
<h3>
Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>
A bit of further explanation:
The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.
Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h
For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.
Answer:
You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.
The probability of selecting a red marble the first time is 1313.
(This is because 4 out of 12 marbles are red and412412 reduces to 1313.
The probability of selecting a red marble the second time is 1313.
The marble selections are independent and you can multiply the two probabilities to get the following:
probability of getting 2 reds = (13)2(13)2
=19=19.
So the probability of getting two reds is 1919.
Base Surface Area = 22
= 4 yards^2
Lateral Surface Area =
2×2√(2/2)^2 + 3^2
2
= 12.649110640674 yards^2
Total Surface Area = 16.649110640674 yards^2
Your Answer: 16.60 rounded to the nearest tenth.
