Maya mailed 3 packages. their weights were 4.5 lbs,2.75 lbs,and 3.4 lbs.

1 answer:

8 0

The total weight was 10.65

Explanation: Since there is only one number in the hundredth place, i didn’t need to add. Instead i put that number as my hundredth place AKA 5. then i added the tenth place which was 5+7+4 which = 16. i carried the one over. then i added the ones place. 4+2+3= 9. the one i carried over got added to the 9. therefore my final answer was 10.65

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3xy'+y=12x find general solution

Eduardwww [97]

The equation is linear, as you can write

$3xy'+y=12x\implies y'+\dfrac1{3x}y=4$

An integrating factor would be

$\mu(x)=\exp\left(\displaystyle\int\frac{\mathrm dx}{3x}\right)=x^{1/3}$

Multiplying both sides of the ODE by this yields

$x^{1/3}y'+\dfrac1{3x^{2/3}}y=4x^{1/3}$

where the LHS is a derivative:

$\dfrac{\mathrm d}{\mathrm dx}\left[x^{1/3}y\right]=4x^{1/3}$

Integrating both sides, we get

$x^{1/3}y=4\displaystyle\int x^{1/3}\,\mathrm dx$
$x^{1/3}y=3x^{4/3}+C$
$y=3x^{3/3}+Cx^{-1/3}=3x+\dfrac C{x^{1/3}}$