The answer to the question is d
Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]
X' = U - X
= {1,2,3,4,5,6} - {1,4,5}
= {2,3,6}
(ZUX') = {2,3,5} U {2,3,6}
= {2,3,5,6}
(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}
= {2}
Answer:
The answer is<u> D.</u> h+3/j+6.
Step-by-step explanation:
Given:
The equation h + 3 = jk + 6k.
Now, to get the mathematical expression.
So, taking 
common on R.H.S we get:
Then, dividing both sides by 
we get:
Thus,
Therefore, the answer is D. h+3/j+6.
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
Answer:
3
Step-by-step explanation:
if you plug in 3 for x, it becomes 2(3)-7=-1
then 6-7=-1
-1=-1
