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yKpoI14uk [10]
2 years ago
8

Find the Percent:

Mathematics
1 answer:
ycow [4]2 years ago
6 0

Step-by-step explanation:

First, find 12 percent of 1,150,

12 percent of 1,150 = 138.

Now, add 1,150 + 138,

1,150 + 138 = 1,288

Hope I helped, if not, at least I tried.

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if alpha and beta are the zeroes of the polynomial f(x) = 6x² + x - 2, find the value of 1/alpha + 1/beta - alphabeta​
finlep [7]

Answer:

let alpha be x and beta be y

Step-by-step explanation:

x+y= -b/a

x+y=-1/6

and xy= c/a

xy= -1/3

according to question

1/x+1/y -xy =(x+y)/xy-xy

(-1/6)/(-1/3)-(-1/3)

1/2+1/3

the answer is 5/6

7 0
3 years ago
Evaluate x = 4 and y=5.<br>X? + 2(x + y)​
777dan777 [17]

4+2(4+5)

4+2*4+2*5=

4+8+10=

22

6 0
3 years ago
What are the 12 rules of shading inequalities?
ivann1987 [24]
I don't know all 12, but I can tell you some.

1. Shade the side of the line that satisfies the inequality.
2. If the inequality sign has an "or equal to" line under it, make the line on the graph connected.
3. If the inequality sign does not have an "or equal to" line under it, make the line on the graph dashed.
4. Isolate y (or the variable that is being used), and keep it on the left side of the inequality.
3 0
3 years ago
This is 22 points
AURORKA [14]
Let the initial number of girls be x, this represents 40% of the dancers.
Total number of dancers will therefore be:
100/40*x=2.5x
When 15 more girls joined, the new number of girls was:
x+15 this represents the total percentage of 52%. The new number of dancers became:
2.5x+15:
therefore the new percentage of girls can be expressed as follows:
(new number of girls)/(new number of dancers)×100
(x+15)/(2.5x+15)×100=52
(x+15)/(2.5x+15)=0.52
x+15=0.52(2.5x+15)
x+15=1.3x+7.8
15-7.8=1.3x-x
7.2=0.3x
x=7.2/0.3=24
The number of students after additional number of girls will be:
2.5x+15
=2.5×24+15
=60+15
=75 students

4 0
3 years ago
Read 2 more answers
for the inequality Y is less than or equal to 9 Jasmine says 9 and 0 are both solutions is she correct
Natali5045456 [20]
Yes because the solution can either be equal to 9 or less than 9 and 9=9 and 0<9 so they can both be solutions
7 0
2 years ago
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