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Dimas [21]
2 years ago
9

Rabbits can exhibit a number of colors in their coats: black, white, tan, brown, red, and grey. A disease randomly kills off mos

t of the population and leaves only black and grey rabbits. Future generations are only black or grey. What is the term used to describe this phenomenon
Mathematics
1 answer:
Marysya12 [62]2 years ago
4 0

Answer:

Genetic drift

Step-by-step explanation:

I took da test

You might be interested in
How do i know when to add or subtract in an angle equation?
madam [21]

Answer:

17

Step-by-step explanation:

< ABD = <ABC + < CBD

Substitute in what we are given

87 = 9x-1 +   6x+58

Combine like terms

87 = 15x +57

Subtract 57 from each side

87-57 =15x +57-57

30 = 15x

Divide by 15

30/15 =15x/15

2=x

We want to find <ABC

<ABC = 9x-1

         = 9*2-1

         =18-1

      =17

7 0
3 years ago
Indicate whether the study is an observational study or a controlled experiment. A group of boys is randomly divided into two gr
MariettaO [177]

Answer:

Controlled Experiment

Step-by-step explanation:

The controlled experiment involves the experiment in which all factors are considered as constants whereas one factor is not fixed and that one is independent variable whose effect is to be tested. In short,  in controlled experiment one group of data contains control group and one or more other groups are examined by considering all other factors constant except for one factor. The control group is the group that doesn't receive any treatment whereas treatment is applied to experimental group and then effect of treatment is measured through comparing both groups.  

Here group of boys is divided in to two groups

The group watched violent cartoon= Experimental group

The group watched  cartoons without violence= Control group

The researchers want to know whether the violent actions of boys are linked to violent cartoon  and for this purpose these boys are divided into experimental group and control group and after 1 hour of cartoons watching the researcher will observed boys for next two hours.

Hence the study is Controlled experiment.

6 0
3 years ago
(-6 – 0, y +4)<br><br> HHHEEEEELLLPPP!!!!! need for tonight!!!
elena55 [62]
Do you need it solved or graphed?

6 0
4 years ago
To the nearest tenth, what is the perimeter of the triangle with vertices at (−2, 3), (3, 6), and (2, −2)?
katovenus [111]

9514 1404 393

Answer:

  20.3

Step-by-step explanation:

The distance formula can be used to find the side lengths.

  d = √((x2 -x1)^2 +(y2 -y1)^2)

For the first two points, ...

  d = √((3 -(-2))^2 +(6 -3)^2) = √(5^2 +3^2) = √34 ≈ 5.83

For the next two points, ...

  d = √((2 -3)^2 +(-2-6)^2) = √(1 +64) = √65 ≈ 8.06

For the last and first points, ...

  d = √((-2-2)^2 +(3-(-2)^2) = √(16 +25) = √41 ≈ 6.40

Then the sum of the side lengths is ...

  5.83 +8.06 +6.40 = 20.29 ≈ 20.3

The perimeter of the triangle is about 20.3 units.

7 0
3 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
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