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3 years ago

Find x, please. They’re vertical angles so x will be the same for both

Mathematics

1 answer:

Kazeer [188]3 years ago

6 0

Answer:

23.

Step-by-step explanation:

5x + 20 = 3x + 66

Subtract 20 from both sides and 3x from both sides

5x - 3x + 20 - 20 = 3x - 3x + 66 - 20

5x - 3x = 66 - 20

2x = 46

x = 23.

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Abcd is a parallelogram determine the length of BE

g100num [7]

Answer:

B) 102 units

Step-by-step explanation:

The diagonals of a parallelogram bisect each other. This means ...

BE = ED

3 -9x = -8x +14

-11 = x . . . . . . . . . . . . add 9x -14

BE = 3 -9x = 3 -9(-11) = 3 +99

BE = 102 units

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2 years ago

Peter can ride his bike for 60 miles in 1 hour less time than it

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Step-by-step explanation:

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3 years ago

HELP ASAP

Zanzabum

The median is the middle value in a list ordered from smallest to largest.

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2 years ago

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Perform the indicated operation. 11(-2) 22 9 -9 -22

ASHA 777 [7]

Answer:

-22

Step-by-step explanation:

When you multiply a positive and negative number together, it becomes negative.

Multiplication is repetitive addition.

11(-2) = -11 + -11 = -22

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3 years ago

A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1

Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth $= \$ 17,000$

depreciates by $\frac{1}{2}$ in 3 years.

time= 19 years

depreciates rate=?

Using formula:

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$\to A_t=A_0(1-\frac{r}{100})^t$

calculates depreciate value in 3 year $= \frac{1}{2} \times 17,000$

$= 8,500$

so,

$A_t=8,500\\\\A_0=17,000\\\\t=3\ years$

$\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%$

depreciates rate= 20%

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238$

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3 years ago

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