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2 years ago

Can you guide me through the steps of finding the area of a circle?

Mathematics

1 answer:

andreyandreev [35.5K]2 years ago

5 0

Answer:

A=(3.14)r²

Step-by-step explanation:

First you find your radius if it is a diameter you divide it by 2

Second you multiply the radius by pi (π=3.14)

lastly you square your answer

hope this helps!

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Algebra 1 Grade 9

Whitepunk [10]

You are describing where I live only that temperature is a bit low. I'm sorry to say it is neither one.

t_daily = t_average +/- 5

The highest temperature would be

t_daily = t_average + 5

t_daily = 1 + 5

t_daily = 6

================

The Lowest temperature would be

t_daily = t_average - 5

t_daily = 1 - 5

t_daily = - 4

Sounds about right for December.

6 0

3 years ago

Jim is building a model of a square pyramid for a class project. The side length of the square base is 20 inches and the slant h

Brums [2.3K]

Answer:

$SA = 920 inches^{2}$

Step-by-step explanation:

Given Data:

Slant height of square pyramid = l = 13 inches

Base edge of square pyramid = s = 20 inches

To Find Out:

Surface area of square pyramid = SA = ?

Formula:

$SA = s^{2} + 2 * s * l$

Solution:

$SA = s^{2} + 2 * s * l$

$SA = 20^{2} + 2 * 20 * 13$

$SA = 400 + 520$

$SA = 920 inches^{2}$

3 0

2 years ago

Todd has been helping his grandmother vanilla ice cream. Yesterday morning they made 4.5 quarts of ice cream. They are going to

netineya [11]

Answer:

Todd will need 9 pint-sized containers to store 4.5 quarts of ice cream.

8 0

2 years ago

(6a^-4b^2)^-2 for the ^ it is an exponent,

larisa [96]

Negative exponents work the same as positive ones, except you have to consider the inverse of the base.

So, if for example $4^3 = 64$ , in the same fashion you have

$4^{-3} = \dfrac{1}{4^3} = \dfrac{1}{64}$

So, negative exponents lead to a fraction with numerator 1 and denominator the same expression, but with positive exponent.

So, in your case, let's work with the inner parenthesis first:

$6a^{-4}b^2 = 6 \dfrac{1}{a^4}b^2 = \dfrac{6b^2}{a^4}$

Now, if we want to raise this to the negative two, we have

$\left(\dfrac{6b^2}{a^4}\right)^{-2} = \dfrac{1}{\left(\frac{6b^2}{a^4}\right)^2}} = \dfrac{1}{\frac{36b^4}{a^8}} = \dfrac{a^8}{36b^4}$

4 0

3 years ago

Solve this equation: 3x – 5 - x = 134

Zepler [3.9K]

Answer:

(3x - x) :v

Step-by-step explanation:

3x - 5 - x =134

2x - 5 = 134

2x = 139

x = 139/2

8 0

2 years ago

Read 2 more answers