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sammy [17]
2 years ago
5

What is the following product? startroot 30 endroot times startroot 10 endroot

Mathematics
1 answer:
aleksandrvk [35]2 years ago
7 0

Answer:

Hello there! 10 square of 3

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the length of a rectangular garden is one foot les than five times it's width. the area is 18 square feet find de width and leng
Harlamova29_29 [7]
The width is 2 and the length is 9 because 9 times 2 is 18 and 2 times 5 is 10. 10 minus 1 is 9 which then again 9 times 2 is 18 which is the area.
7 0
3 years ago
What is the remainder when f(x) = x2 + 14x − 8 is divided by (x − 3)?
ser-zykov [4K]

X^2 +14x -8 / x-3

= x + 17 with a remainder of 43

See attached picture for solution.

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3 years ago
a scale drawing has scale 1:20. in real life the length of a boat is 150m what is the length of the boat on the scale drawing. A
barxatty [35]
To find the size of the scale, we must divide its size by 20 (because the scale is 1:20). Doing that we get 150/20=7.5m=750cm. Hope this helps!
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Read 2 more answers
28. $400 is divided between Kas, Jaspar and Jae so that Kas has twice
Inga [223]

Let's define our variables before anything else:

Kas = S

Jaspar = R

Jae = E

$400 is divided between Kas, Jaspar and Jae

This means S + R + E = 400

Kas has twice  as much as Jaspar

This means that S = 2R

Jaspar has three times as much as Jae

This means that R = 3E

Because both of our smaller formulas have R, let's replace everything in the first formula with R

S + R + E = 400

plug in values

2R + R + R/3 = 400

multiply everything by 3 to get rid of the denominator

6R + 3R + R = 1200

add

10R = 1200

divide

R = 120

So Jaspar receives $120

3 0
4 years ago
In how many ways can the letters of the word COMPUTER be arranged in a row if the letters C and O can not stand next to each oth
nirvana33 [79]

Answer:

35280ways

Step-by-step explanation:

let X be the number of ways the letters can be arranged with no restriction,

let M be the number of ways they can be arranged if the letters C and O must stand together,

and let the number of ways the letters C and O can be arranged if they can not stand together.

X=8!

M= 7!

N=X–M=8!–7!=35280 ways

3 0
2 years ago
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