Events:
1 ≤ n ≤ 100
A=x is a perfect square, i.e. x=n^2
B=x is odd, i.e. n is odd
P(A|B)
=P(A∩B)/P(B) by definition of conditional probability
(reads Probability that the number is a perfect square given that it is odd)
Since there are 10 perfect squares between 1 to 100 (1,4,9,16,25,36,49,64,81,100), out of which 5 are odd {1,9,25,49,81)
So P(A∩B)=5/100
P(B)=probability of odd x {1,3,5,7,.....95,97,99}
= 50/100=1/2
Therefore
P(A|B)=(5/100)/(1/2)=1/10
Answer:
Hey its D I think.
Step-by-step explanation:
1. The way I think of it is putting a negative number in front as a x value.
I chose -1,-2 and -3.
-1-5<0 -2-5<0 -3-5<0
-6<0 -7<0 -8<0
The reason why it satisfies because negative number are all real numbers less than one. Hope that helps:)
Distance = SQRT(x^2+y^2)
x = 4 - (-2) = 6
y = 3 - 2 = 1
distance = SQRT(6^2 + 1^2) = SQRT(36+1) = SQRT(37) = 6.1
Answer:
Step-by-step explanation:
4/7 x + 70 cm^3 = 3/4 x Subtract 4/7 x from both sides
3/4 x - 4/7 x = 70 cm^3 The lowest common denominator is 28
5x = 70*28
5x = 1960 Divide by 5
x = 1960/5
x = 392 cc
The answer for this equation is q=5
