How to evaluate (-5)^-3 when 5 is a prime number.
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Answer:
1) The inequality for the given system are
y ≥ 4x - 4
y ≥ x - 1.5
2) The test point (0,0) satisfies both of the inequalities in the system represented by the graph.
Step-by-step explanation:
Given : A graph showing a system of inequalities.
We have to find the system of inequality.
For line 1)
The points that cut the x and y axis are (1,0) and (0,-4)
Thus, we can find the equation of line using two given point.
Since the general equation of line is y = mx + c
Where m is slope and c is y intercept
Slope is find as
Substitute, we get,
Slope is 4.
Thus, equation becomes y = 4x + c
For c put (0,-4) in the above equation , we have,
-4 = 4(0) + c ⇒ c = -4
Thus, equation becomes y = 4x - 4
For inequality take a test point (0,0) and we check for which inequality it satisfies the graph region
For (0,0)
y = 4x - 4 becomes 0 = - 4 is satisfied when 0 > -4
thus, the inequality becomes y ≥ 4x - 4
Since, the line is a solid so it will take up equality sign too.
For line 2)
The points that cut the x and y axis are (1.5,0) and (0,-1.5)
Thus, we can find the equation of line using two given point.
Since the general equation of line is y = mx + c
Where m is slope and c is y intercept
Slope is find as
Substitute, we get,
Slope is 1.
Thus, equation becomes y = x + c
For c put (0,-1.5) in the above equation , we have,
-1.5 = (0) + c ⇒ c = - 1.5
Thus, equation becomes y = x - 1.5
For inequality take a test point (0,0) and we check for which inequality it satisfies the graph region
For (0,0)
y = x - 1.5 becomes 0 = -1.5 is satisfied when 0 > - 1.5
thus, the inequality becomes y ≥ x - 1.5
Since, the line is a solid so it will take up equality sign too.
Thus, the inequality for the given system are
y ≥ 4x - 4
y ≥ x - 1.5
Also, The test point (0,0) satisfies both of the inequalities in the system represented by the graph.
