Answer:
C. I & III
Step-by-step explanation:
I simplifies to ...
2(6x +15 -5x) +4 = 40
12x +30 -10x +4 = 40
2x +34 = 40
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II simplifies to ...
40 = 2(15 -x) +4
40 = 30 -2x +4
40 = -2x +34 . . . . . . not equivalent to I (sign of x-term is different)
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III simplifies to ...
12x +30 -10x +4 = 40
2x +34 = 40 . . . . . . equivalent to I
___
I & III are equivalent
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Answer:
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Answer:
only one solution
Step-by-step explanation:
Complete question:
<em>Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x − y = 2 3x + y = −6 one and only one solution infinitely many solutions no solution Find the solution, if one exists. (If there are infinitely many solutions, express x and y in terms of the parameter t. If there is no solution, enter NO SOLUTION.) (x, y) </em>=
Given the expression
2x − y = 2 .... 1
3x + y = −6 ..... 2
We are to determine the number of solution the equation has:
Add equation 1 and 2
2x + 3x = 2 - 6
5x = -4
x = -4/5
Substitute x = -4/5 into 1
From 1: 2x − y = 2 .... 1
2(-4/5) - y = 2
-8/5 - y = -2
-y = -2+8/5
-y = -10+8/5
-y = -2/5
y = 2/5
<em>Since the value of x and y are just 1 hence the system of equations has ine solution</em>
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