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LenaWriter [7]
3 years ago
13

Find the quotient of 2/5 and 4/5

Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

10/20 or 1/2

Step-by-step explanation:

Heres a picture to explain:

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Y + 3 = -2x2+5<br> are these a quadratic function
Sergio039 [100]

Answer:

Yes

Step-by-step explanation:

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3 years ago
(4x +7)<br> (10x - 23)<br> (7x - 35)<br> What is the value of 2? Fill in the blank with the answer
MatroZZZ [7]

Answer:

x = 1. x = - 5/4

(Plz excuse me if it's wrong lol)

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3 years ago
Is 45.07 x 3.25 an overestimate
vitfil [10]

Answer:

No i dont think it is

Step-by-step explanation:

srry if im wrong :C

8 0
3 years ago
Read 2 more answers
Help me class8 (surds)​
Mashcka [7]

Answer:

  • \cfrac{991\sqrt{2} }{80}

Step-by-step explanation:

For a start simplify each of the roots:

  • \sqrt{72} =\sqrt{36*2} =6\sqrt{2}
  • \sqrt{50} =\sqrt{25*2} =5\sqrt{2}
  • \sqrt{128} =\sqrt{64*2} =8\sqrt{2}
  • \sqrt{98} =\sqrt{49*2} =7\sqrt{2}

Now simplify the expression in steps:

\sqrt{72}-\cfrac{48}{\sqrt{50} }  -\cfrac{45}{\sqrt{128} }  +2\sqrt{98} =

6\sqrt{2}-\cfrac{48}{5\sqrt{2} }  -\cfrac{45}{8\sqrt{2} }  +2*7\sqrt{2} =

6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} }  +14\sqrt{2} =

20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =

20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =

\sqrt{2} (20-7\cfrac{49}{80} )=

\sqrt{2} *12\cfrac{31}{80} =

\cfrac{991\sqrt{2} }{80}

3 0
2 years ago
I don't understand how to do this problem. help ? ( number 13)
OverLord2011 [107]
5x- 10 = 20
5x -10 +10 = 20 +10
5x = 30
5x/5 =30/5
x = 6
7 0
3 years ago
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