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GenaCL600 [577]
3 years ago
9

Y + 3 = -2x2+5 are these a quadratic function

Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

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2 1/8 x 2 6/9 <br><br> (Multiplying fractions)
IrinaVladis [17]

Answer:

17/6

Step-by-step explanation:

Start off with

2 1/8 * 2 6/9

Convert mixed number into improper fraction

17/8

reduce fraction with 3

17/8 * 2 * 2/3

Reduce numbers with GCD 2

17/4 * 2/3

Repeat

17/2 * 1/3

Multiply fractions

17*1/2*3

You then get...

17/6!

[Alternative forms: 2 5/6, 2.83]

5 0
4 years ago
What is the area of a circular region whose diameter is 10 centimeters?
stepan [7]

Answer:

78cm

Step-by-step explanation:

d = 10

area of a circle = πr^2

22/7 × 5 × 5

78.5cm

6 0
3 years ago
Find the vertex of the quadratic function
Galina-37 [17]

Answer:

(1.5,2.5)

Step-by-step explanation:

f(x) = 2x^2 - 6x + 7

Take the first derivative and set it equal to 0 (the slope is 0 at the vertex)

f'(x) = 4x -6

0 = 4x - 6

4x = 6

x = 3/2 or 1.5

If x = (3/2), then y = 2(3/2)^2 - 6(3/2) + 7

y = 2(9/4) - 18/2 + 7

y = (9/2) - 2

y = 2.5

See attached graph.

8 0
2 years ago
Which of the following could be the graph of this equation?
Anna35 [415]

Answer: OPTION C.

Step-by-step explanation:

Given a function f(x), the range of the inverse of f(x) will be the domain of the function f(x) and the range of the domain of f(x) will be the range of the inverse function.

For example, if the point (2,1) belongs to f(x), then the point (1,2) belongs to the inverse of f(x).

Observe that in the graph of the function f(x) the point (-3,1) belongs to the function, then the point (1,-3) must belong to the inverse function.

Therefore, you need to search the option that shown the graph wich contains the point (1,-3).

Observe that the Domain f(x) is (-∞,0) then the range of the inverse function must be (-∞,0).

This is the graph of the option C.

4 0
4 years ago
Solve the quadratic equation (x-3)2 = 49
Tresset [83]
27.5, because 27.5-3=24.5 and 24.5x2= 49
3 0
3 years ago
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