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Nata [24]
2 years ago
9

Bert can paddle his kayak at a maximum speed of 270metersperminute. If he paddles across a lake at one-third of his top speed fo

r 8minutes, how far will he move?
Mathematics
1 answer:
nikdorinn [45]2 years ago
8 0

Answer:

4

Step-by-step explanation:

You might be interested in
The graph shows a function f(x). Determine the following values.
wel

Answer:

f^-1(4) = 2

f^-1(-5) = -4

f^-1(0) = 0

Step-by-step explanation:

To find the inverse of the function, we simply switch the places of x and y

You simply find the value given on the y-axis and trace to the x-axis

Thus, we have the following ;

f^-1(4) = 2

f^-1(-5) = -4

f^-1(0) = 0

7 0
3 years ago
If one out of 12 students at a school share a locker, how many share a locker in a school of 456 students
ahrayia [7]
456÷12= 38

I pretty sure... I hope this helps!
8 0
3 years ago
Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)
dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0
2 years ago
20. Lee uses Bill Payer from his bank account to pay his internet bill. Lee pays the same amount each month.
NARA [144]
It's the same amount each month, for a year. So:
total money ÷ times money was taken out= how much has been taken out.

$600÷12=50
3 0
3 years ago
Help on this sh*t from 2-6
zlopas [31]

Answer:

1. x = 15, y = 8

2. m∠MSN = 90°

3. x = 20

4. y = 9

5. x = 8, m∠PQS = 24, m∠SQR = 66

6. y = 15, m∠RPT = 55, m∠TPW = 35

Step-by-step explanation:

1. to solve for y

9y + 18 = 90

9y + 18 - 18 = 90 - 18

9y = 72

9y/9 = 72/9

y = 8

to solve for x

5x + x = 90

6x = 90

6x/6 = 90/6

x = 15

2. m∠MSN = 90°, because ∠MSN is a right angle, which is equal to 90

3. To find x

3x + 10 + x = 90

3x + x = 4x

4x + 10 = 90

4x + 10 - 10 = 90 - 10

4x = 80

4x/4 = 80/4

x = 20

4. To find y

7y - 3 + 3y + 3 = 90

7y + 3y = 10

-3 + 3 = 0

10y = 90

10y/10 = 90/10

y = 9

5. To find x

3x + 8x + 2 = 90

3x + 8x = 11x

11x + 2 = 90

11x + 2 - 2 = 90 -2

11x = 88

11x/11 = 88/11

x = 8

To find ∠PQS

∠PQS = 3x

x = 8

so 3(x) = 3(8)

3(8) = 24

so ∠PQS = 24

To find ∠SQR

∠SQR = 8x + 2

x = 8

so ∠SQR = 8(x) + 2 = 8(8) + 2

8(8) + 2

= 64 + 2

= 66

6. To find y

4y - 5 + 2y + 5 = 90

4y + 2y = 6y

-5 + 5 = 0

6y = 90

6y/6 = 90/6

y = 15

To find ∠RPT

∠RPT = 4y - 5

y = 15

so ∠RPT = 4y - 5 = 4(15) - 5

4(15) - 5

= 60 - 5

= 55

To find ∠TPW

∠TPW = 2y + 5

y = 15

so ∠TPW = 2y + 5 = 2(15) + 5

2(15) + 5

= 30 + 5

= 35

7 0
3 years ago
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