We will see that the probability of picking two orange marbles without replacement is 0.23
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How to get the probability?</h3>
If we assume that all the marbles have the same probability of being randomly picked, then the probability of getting an orange marble is given by the quotient between the number of orange marbles and the total number of marbles, this gives:
P = 6/12 = 1/2
And then we need to get another orange marble, without replacing the one we picked before, this time there are 5 orange marbles and 11 in total, so the probability is:
Q = 5/11
Finally, the joint probability (of these two events happening) is the product of the probabilities, so we get:
P*Q = (1/2)*(5/11) = 0.23
If you want to learn more about probability, you can read:
brainly.com/question/251701
Answer: The table and figure are given below,
Solution:
The given equation is 
.
put x=0 in the equation.
Similarly find the values of y at different values of x. The values are shown in the table.
From table it is notices that the value of y=-2 for x=0, y=-1 for x=3, y==-3 for x=-3, y=0 for x=6.
Plot these points in the coordinate plane and joint them by a straight line.
The gra his shown in below figure.
Step-by-step explanation:
Comparing Rational Numbers:
1/7 , 3/9 , 0.2
0.142857... , 0.333333... , 0.2
a= 1/7
b= 0.2
c= 3/9
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Hope this Helps!!!</em></u></h3><h3><u><em>
:)</em></u></h3>
Answer:
Mean = 30.68
Standard deviation = 6.095
Two standard deviations above the mean = 42.87
Step-by-step explanation:
Given the following data :
21; 21; 22; 23; 24; 24; 25; 25; 28; 29; 29; 31; 32; 33; 33; 34; 35; 36; 36; 36; 36; 38; 38; 38; 40
Mean = Σ(x) / n
n = 25
Σ (X) = 767
Mean (m) = 767 / 25
Mean (m) = 30.68
Standard deviation : sqrt[Σ(x - m) / n]
Using a calculator :
Standard deviation = 6.095 ( 2 decimal places)
2 standard deviations above the mean :
Mean + 2(standard deviation)
Mean + 2(6.095)
30.68 + 12.19
30.68 + 12.19
= 42.87
22. -6
-14+8=-6
23. -8
-3+-5=-8
24. 4
17-13=4
i’m not 100% sure on these but i’m pretty sure i’m right, hope this helps !
ps. report bs answers to prevent loss of points
