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sasho [114]
3 years ago
9

During the summer, Hector does yard work, and Geri babysits.To show their earnings, Hector makes a graph, and Geri makes a table

. Which statement is true?
Math item stem image

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
6 0

Answer:

Hector earns $6.50 more per hour than geri

Step-by-step explanation:

VLD [36.1K]3 years ago
4 0

I think that when you asked this question, no one answered because there is not enough information. I also got this problem and there is in fact, a table and a graph.

Step-by-step explanation:

for Hector, it only shows a y and x graph and for Geri it shows a table. let´s call the graph the ¨h¨ graph (for Hector) and the table is going to be called the ¨g¨ graph (for Geri)

on the h graph, it shows that y/x = dollars/time for Hector,

on the g table, it shows that Geri is getting paid $25.50 for each 3 hours and it keeps increasing within each input and output.

your y = your dollars

your x = your time

we are looking for slope and we need $15 over hours

15/x

the answer is that Hector earns $6.50 more than Geri

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There are 15 pieces of fruit of bowl and six our apples what percent are apples.
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Calculate the following absolute value |-1-1+2|-|-1+2|-|-2|
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3 years ago
Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

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3 years ago
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