Answer:
a) (4x® - 5x + 15) - (11 - 7x - 2x)
b)(9x- 6x® - 7x-2) + (10x - 8x + 11)
Step-by-step explanation:
a) (4x® - 5x + 15) - (11 - 7x - 2x)
b)(9x- 6x® - 7x-2) + (10x - 8x + 11)
Answer: There are two solutions and they are
theta = 135
theta = 225
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Explanation:
Recall that x = cos(theta). Since the given cosine value is negative, this indicates x < 0. Theta is somewhere to the left of the y axis, placing it in quadrant 2 or quadrant 3.
It turns out there are two solutions, with one solution per quadrant mentioned above. Use the unit circle to find that the two solutions are:
theta = 135
theta = 225
You're looking for points on the unit circle that have x coordinate equal to x = -sqrt(2)/2. Those two points correspond to the angles of 135 and 225, which are in quadrants 2 and 3 respectively.
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I recommend using your calculator to note that
-sqrt(2)/2 = -0.70710678
cos(135) = -0.70710678
cos(225) = -0.70710678
The decimal values are approximate. Make sure your calculator is in degree mode. Because those three results are the same decimal approximation, this indicates that cos(135) = cos(225) = -sqrt(2)/2.
Answer:
it is very simple we can answer it's to simple
Step-by-step explanation:
let me explain
for it is straight
for arb it is also simple you have to do arb because there is made triangle
prq there is also a triangle
now please mark me as brainlist
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