Carlos is wrong since when subtracted 2175 from 1833 you get 342 so that's about one third of what he said.
Answer:
4
Step-by-step explanation:
5 divided by 3 times
5/5/5=.2
.2*20=4
let the goldfish be x and the guppies be y
4x + 3y = 29...equ(1)
3x + 5y = 30...equ(2)
multiplying equation 1 by 5 and equation 2 by 3
20x + 15y = 145...equ(1)
9x + 15y = 90...equ(2)
subtracting equation 2 from 1
11x = 55
∴x = 5
substituting the value of x into equation
4(5) + 3y = 29
20 + 3y = 29
3y = 9
∴y =3
<span>lim (x → π/2) (sinx)^(tanx)
= lim (x → π/2) e^[(tanx) ln (sinx)]
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1)
lim (x → π/2) (tanx) ln (sinx)
= lim (x → π/2) [ln(sinx) / cotx]
Using L'Hospital'stheorem,
= lim (x → π/2) [- cotx / cosec^2 x]
= 0
Plugging in ( 1 ),
required limit = e^0 = 1
=>Answer is 1.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
