Miss Tamika just started an art class. She had 10 children enrolled for the first class. · Before she began the art lesson, she
told each of the children to shake hands with ! each of the other children and introduce I themselves. Miss Tamika did not include i herself because she had already met each i of the children. How many handshakes were there between all of the children?
1 answer:
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9514 1404 393
Answer:
(3) 12
Step-by-step explanation:
Let x represent the length of leg XY. Then the length of YZ is x/2 and the area of the right triangle is ...
A = 1/2bh
A = 1/2(x)(x/2) = x²/4
36 = x²/4 . . . . . use the given value for area
144 = x² . . . . . . multiply by 4
√144 = 12 = x . . . . . take the square root
The length of leg XY is 12 cm.
Answer:
Step-by-step explanation:
The summary of the given data includes;
sample size for the first school = 42
sample size for the second school = 34
so 16 out of 42 i.e = 16 and 18 out of 34 i.e
= 18 have ear infection.
the proportion of students with ear infection Is as follows:
= 0.38095
= 0.5294
Since this is a two tailed test , the null and the alternative hypothesis can be computed as :
level of significance ∝ = 0.05,
Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.
The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.
The pooled standard error can be computed by using the formula:
The test statistics is ;
z = - 1.368
Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.
Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools