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alexgriva [62]
3 years ago
13

Jake owns twice as many DVDs as Louis.Bo has sixty fewer DVDs than five times Louis’s collection. If Jake and Bo have the same a

mount of DVDs how DVDs are in Louis’s collection?
Mathematics
1 answer:
almond37 [142]3 years ago
4 0

There are 20 number of DVD's in Louis collection

<em><u>Solution:</u></em>

Let "J" be the number of DVD's with Jake

Let "B" be the number of DVD's with Bo

Let "L" be the number of DVD's with Louis

<em><u>Given that Jake owns twice as many DVDs as Louis</u></em>

So we can say,

number of DVD's with Jake = 2(number of DVD's with Loius)

J = 2L  ------ eqn 1

<em><u>Given that Bo has sixty fewer DVDs than five times Louis’s collection</u></em>

So we can say,

number of DVD's with Bo = 5 times number of DVD's with Louis - 60

B = 5L - 60 ---- eqn 2

<em><u>Given that Jake and Bo have the same amount of DVDs</u></em>

number of DVD's with Jake = number of DVD's with Bo

J = B ---- eqn 3

<em><u>Let us solve eqn 1, 2, 3 to find value of "L"</u></em>

From eqn 1 and eqn 3,

2L = B  ----- eqn 4

Substitute eqn 4 in eqn 2

2L = 5L - 60

2L - 5L = -60

-3L = -60

<h3>L = 20</h3>

Thus there are 20 number of DVD's in Louis collection

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