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Mkey [24]
1 year ago
5

Which expression shows 48 + 36 written as a product of two factors

Mathematics
1 answer:
oksano4ka [1.4K]1 year ago
6 0

Answer:

12(4+3)

Step-by-step explanation:

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I’ll give brainliest answer so i need to solve for y and convert these to slope intercept form.
Crazy boy [7]

Answer:

2. 9x+4y=16

    -9x        -9x

4y=-9x+16

----  ----  ----

4      4      4

y= -9x

     --- +4

      4

4. 4x+3y=-9

  -4x         =4x

     3y=-4x-9

     ---    --- ---

     3       3  3

y= -4x

    ---- - 3

      3

6. 7x-3y=6

  -7x      -7x

       -3y=-7x+6

        ---  ----   ---

       -3    -3    -3

y= 7x

   --- -2

    3

3 0
2 years ago
The cost of renting a jet ski is $65 per hour. Write an equation to find the cost c of renting a
VARVARA [1.3K]

Answer:

65*h=c

Because if it's per hour c is dependent on the amount of hours.

3 0
2 years ago
Help asap do all show work
love history [14]

y=-x

slope for perp line = 1

2y=-x+6

y=-1/2x +3

slope for perp line = 2

15.

i don’t wanna do all sorry it’s a lot of work so i’ll tell u how to do it instead. first write it in slope intercept form which is

y-y1=m(x-x1)

it’s parallel which means it shares the same slope. if it’s perpendicular it would be opposite reciprocals so for -3/2 the perp slope would be 2/3.

the line is

y+1=3/4(x-4)

we distribute the 3/4 so it’s now

y+1=3/4x-3

then we subtract the 1

y=3/4x-4 is the equation boom done

6 0
2 years ago
Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
2 years ago
I need help for this please
shepuryov [24]

Answer:

its blocked

Step-by-step explanation:

8 0
2 years ago
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