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emmasim [6.3K]
3 years ago
14

1.Solve the following system of equations:

Mathematics
1 answer:
Yuri [45]3 years ago
7 0
C. infinitely many solutions
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HELP PLEASE <br> I NEED TO CHECK OFF THE TWO FUNCTIONS USED TO CREATE THE GRAPH BELOW
Lelu [443]
Linear and trigonometric
6 0
3 years ago
A table of data is given.
Alecsey [184]

The exponential model best represents the data is B. f(x) = 5(0.2)^x

<h3>How to determine the exponential model?</h3>

From the table of values, we have the following points:

(x, y) = (0,5) and (1,1)

An exponential model is represented as:

y = ab^x

Substitute (x, y) = (0,5)

5 = ab^0

5 = a

This gives

a = 5

So, we have:

y = 5b^x

Substitute (x, y) = (1,1)

1 = 5b^1

This gives

5b = 1

Divide by 5

b = 0.2

Substitute b = 0.2 in y = 5b^x

y = 5(0.2)^x

Hence, the exponential model best represents the data is B. f(x) = 5(0.2)^x

Read more about exponential model at:

brainly.com/question/2456547

#SPJ1

8 0
2 years ago
Please help me solve this correct answer gets brainlist
Inessa [10]

Answer:

12.449899598

Step-by-step explanation:

You would use pythagoras thereom.

C^2=A^2+B^2

The hypotenuse is C (which is the longest side of the triangle - 18).

18×18=13×13+B^2

324=169+B^2

324-169=B^2

155=B^2

Square root B to get B on it's own which would be 12.449899598.

7 0
3 years ago
In the following figure CB is perpendicular to AB, and CD bisects angle ACB. Find angle DBF
zaharov [31]
Measure angle ACD = 3x - 2
measure angle BCD = 5x - 20
measure angle ACD = measure angle BCD
3x - 2 = 5x - 20
-2 = 2x - 20
18 = 2x
9 = x
x = 9
measure angle BCD = 5x - 20
measure angle BCD = 5(9) - 20
measure angle BCD = 45 - 20
measure angle BCD = 25
measure angle CDA = 90
measure angle BDC = measure angle CDA
measure angle BDC = 90
measure angle DBF = measure angle BCD + measure angle BDC
measure angle DBF = 25 + 90
measure angle DBF = 115
5 0
4 years ago
Read 2 more answers
3y+12=2x in slope-intercept form?
alekssr [168]

\bf \stackrel{\textit{solving for \underline{y}}}{3y+12=2x}\implies 3y=2x-12\implies y=\cfrac{2x-12}{3}\implies y=\cfrac{2x}{3}-\cfrac{12}{3} \\\\\\ y=\cfrac{2}{3}x-4\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

5 0
3 years ago
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