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kogti [31]
2 years ago
14

Using the 68-95-99.7 rule

Mathematics
1 answer:
GaryK [48]2 years ago
8 0

Using the Empirical Rule, it is found that the desired probabilities are given as follows.

a) P(x > 158)  = 0.16.

b) P(149 < x < 152) = 0.135.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Additionally, considering the symmetry of the normal distribution, 50% of the measures are below the mean and 50% are above.

Item a:

158 is one standard deviation above the mean, hence the probability is given by, considering that 32% of the measures are more than 1 standard deviation from the mean:

P(x > 158) = 0.5 x 0.32 = 0.16.

Item b:

Between one and two standard deviations below the mean, hence:

P(149 < x < 152) = 0.5 x (0.95 - 0.68) = 0.5 x 0.27 = 0.135.

More can be learned about the Empirical Rule at brainly.com/question/24537145

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Is x + 3 a factor of P(x) = x³ - 5x² + 3x + 9 ? Explain.​
Ksju [112]

Answer:

no

Step-by-step explanation:

using the Factor theorem.

If (x + h) is a factor of f(x) then f(- h) = 0

for factor (x + 3) then evaluate P(- 3)

P(- 3) = (- 3)³ - 5(- 3)² + 3(- 3) + 9 = - 27 - 45 - 9 + 9 = - 72

since f(- 3) ≠ 0 then (x + 3) is not a factor of P(x)

4 0
2 years ago
A fish aquarium that needs water measures 5ft long by 3 feet wide by 2 feet tall. If Josh only has has 12ft of water, how much m
Pepsi [2]

Answer:

Step-by-step explanation:

18 ft

6 0
4 years ago
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Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
3 years ago
The data set represents the total number of pencils each student in a class needs to sharpen.
Firdavs [7]

Given:

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The correct statement that represents the box plot of the data correctly.

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Divide the data in 2 equal parts.

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Divide each parenthesis in 2 equal parts.

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Here,

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den301095 [7]

Answer:

m=-1 I think thats the right answer

7 0
3 years ago
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