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2 years ago

Solve the system of equations. y=3x+7 y=5x-9

Mathematics

1 answer:

Vesnalui [34]2 years ago

5 0

x=8

y=31

I just plugged in a bunch of numbers until I got it

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Again one question not two

Anettt [7]

Answer: A) 5m = 50; m = 10

Step-by-step explanation:

The diagram shows 5 "m"s, or 5*m equal to 50. Thus, 5m=50.

Because 5m = 50, divide both sides by 5 to get that m = 10

<em>Hope it helps <3</em>

8 0

3 years ago

Read 2 more answers

If you need more than 60% of the students surveyed to like your product how many out of 500 would you have to survey

Mashutka [201]

Here is your answer.

6 0

3 years ago

a company promises to release model every month. each model's battery life will be 6% longer than the previous model's. if the c

Ratling [72]

The number of months that it will take the latest model's battery life to reach 1,008.9 minutes is; 8 months

<h3>How to solve geometric progression?</h3>

Each month, there is an increase by a factor of 0.06 of the previous months model.

From geometric sequence formula of aₙ = ar^(n - 1),

where;

a is first term

r is common ratio

aₙ is nth term

we have;

1,008.9 = 671 * 1.06^(n - 1)

1008.9/671 = 1.06^(n - 1)

In 1.504 = (n - 1) In 1.06

0.408 = (n - 1) * 0.058

n - 1 = 0.408/0.058

n = 7.03 + 1

n ≈ 8 months

Read more about geometric sequence at; brainly.com/question/24643676

#SPJ1

5 0

2 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$