Answer:
315.95 or 316
Step-by-step explanation:
If you multiply it you get 315.95 but that kind of equal sign signifies and the approximate sum so 316.
The answer to this problem is 45. What I did was 12x4.5
To find the number of chaperones, you could find the total number of students that are going on the field trip and then break this number into groups of 8.
(158 + 139)/8
297/8 = 37.125
You will need a minimum of 38 chaperones for the 297 students. If there is any remainder(decimal) you will need an extra chaperone so the groups do not exceed 8.
Answer: the equation will be a^2+b^2=c^2 plug in your info, c^2 will be your hypotenuse or your longest side.
Step-by-step explanation:
Answer:
The lowest time limit in which 95% of the bugs can be found is 11.22 hours.
Step-by-step explanation:
We are given that X is the time in hours required to find a bug in a software system. Assume that X is normally distributed with mean of 3 and standard deviation of 5.
<em>So, X = time in hours required to find a bug in a software system </em>
X ~ N(
)
The z score probability distribution is given by;
Z =
~ N(0,1)
where,
= mean value
= standard deviation
<em>Let the lowest time limit in which 95% of the bugs can be found = </em>
<em />
Now, we have to find the lowest time limit in which 95% of the bugs can be found, i.e.;
P(
<
) = 0.95
P(Z <
) = 0.95
Now, the critical value of
in the z table which given an area of less than 95% is 1.6449, which means;
= 1.6449
= 3 + 8.22 = 11.22
Therefore, the lowest time limit in which 95% of the bugs can be found is 11.22 hours.