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3 years ago

DONT UNDERSTAND AT ALLL

Mathematics

2 answers:

dlinn [17]3 years ago

8 0

Her screen is a triangle duh

Fittoniya [83]3 years ago

6 0

Answer:

finding the area:

146

Step-by-step explanation:

You need to break the image up into 3 pieces. the lower big triangle, the middle square, and the top triangle.

the measuremets of the lower big triangle is 14 and 14.
to find the area, we need to do 1/2 *14*14
this equals 98

The measurements of the square is 4,4.
we multiply 4*4 to get 16

The measurements of the top triangle is 8,8.
We find the area by doing 1/2*8*8
We get 32

lastly, we add up all of our solutions.
we do 98+16+32
we get 146.

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Express 0.125 as a percent.

fenix001 [56]

Answer:

12.5 %

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Which of the following represents a relation that is NOT a function? A. X 7 -5 10 -7 Y 34 32 40 34 B. X -7 -5 -7 2 Y 34 32 40 34

Nostrana [21]

The x-value of -7 shows up more than once in relation ...
B. X -7 -5 -7 2 Y 34 32 40 34

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When there is more than one y-value for an x-value, the relation is NOT a function.

8 0

4 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!

valentina_108 [34]

Answer:

Step-by-step explanation

Cluster- a group of points that close together

symmetry- data is balanced on opposite sides of a point or line

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3 0

3 years ago

What is the recursive formula for this geometric sequence?–2, –16, –128, –1024, ...

Tatiana [17]

Answer:

$b_n=-2\cdot 8^{n-1}$

Step-by-step explanation:

Denote first four terms of the geometrc sequence as

$b_1=-2,\\ \\b_2=-16,\\ \\b_3=-128,\\ \\b_4=-1024.$

Note that

$b_2=b_1\cdot q\Rightarrow -16=-2\cdot 8;\\ \\b_3=b_2\cdot q\Rightarrow -128=-16\cdot 8;\\ \\b_4=b_3\cdot q\Rightarrow -1024=-128\cdot 8.$

Then the common ratio is

$q=8.$

Therefore, the recursive formula for the geometric sequence is

$b_n=b_1\cdot q^{n-1}\Roghtarrow b_n=-2\cdot 8^{n-1}.$

5 0

3 years ago

A Common Measure of Student Achievement, The National Assessment of Educational Progress (NAEP) is the only assessment that meas

vlada-n [284]

Answer:

a) By the central limit theorem we know that if the random variable X="quantitative scores for young women", and we know that this distribution is normal.

$X \sim N(\mu, \sigma=60)$

And we are interested on the distribution for the sample mean $\bar X$ , we know that distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And with that we have the assumptions required to apply the normal distribution to create the confidence interval since the distribution for $\bar X$ is normal.

b) $270.283\leq \mu \leq 279.717$

c) We are confident (99%) that the true mean for the quantitative scores for young women is between (270.283;3279.717)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=275$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=60$ represent the population standard deviation

n=1077 represent the sample size

Part a

By the central limit theorem we know that if the random variable X="quantitative scores for young women", and we know that this distribution is normal.

$X \sim N(\mu, \sigma=60)$

And we are interested on the distribution for the sample mean $\bar X$ , we know that distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And with that we have the assumptions required to apply the normal distribution to create the confidence interval since the distribution for $\bar X$ is normal.

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$275-2.58\frac{60}{\sqrt{1077}}=270.283$

$275+2.58\frac{60}{\sqrt{1077}}=279.717$

So on this case the 99% confidence interval would be given by (270.283;3279.717)

$270.283\leq \mu \leq 279.717$

Part c

We are confident (99%) that the true mean for the quantitative scores for young women is between (270.283;3279.717)

8 0

3 years ago