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S_A_V [24]
2 years ago
13

Find the missing angles of the triangle (number 5)

Mathematics
1 answer:
meriva2 years ago
4 0
M1=62°
m2=50°
m3=49°
m4=50°
m5=89°
m6=1°
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Find the inverse Laplace transforms, as a function of x, of the following functions:
inn [45]

Answer:  The required answer is

f(x)=e^x+\cos x+\sin x.

Step-by-step explanation:  We are given to find the inverse Laplace transform of the following function as a function of x :

F(s)=\dfrac{2s^2}{(s-1)(s^2+1)}.

We will be using the following formulas of inverse Laplace transform :

(i)~L^{-1}\{\dfrac{1}{s-a}\}=e^{ax},\\\\\\(ii)~L^{-1}\{\dfrac{s}{s^2+a^2}\}=\cos ax,\\\\\\(iii)~L^{-1}\{\dfrac{1}{s^2+a^2}\}=\dfrac{1}{a}\sin ax.

By partial fractions, we have

\dfrac{s^2}{(s-1)(s^2+1)}=\dfrac{A}{s-1}+\dfrac{Bs+C}{s^2+1},

where A, B and C are constants.

Multiplying both sides of the above equation by the denominator of the left hand side, we get

2s^2=A(s^2+1)+(Bs+C)(s-1).

If s = 1, we get

2\times 1=A(1+1)\\\\\Rightarrow A=1.

Also,

2s^2=A(s^2+1)+(Bs^2-Bs+Cs-C)\\\\\Rightarrow 2s^2=(A+B)s^2+(-B+C)s+(A-C).

Comparing the coefficients of x² and 1, we get

A+B=2\\\\\Rightarrow B=2-1=1,\\\\\\A-C=0\\\\\Rightarrow C=A=1.

So, we can write

\dfrac{2s^2}{(s-1)(s^2+1)}=\dfrac{1}{s-1}+\dfrac{s+1}{s^2+1}\\\\\\\Rightarrow \dfrac{2s^2}{(s-1)(s^2+1)}=\dfrac{1}{s-1}+\dfrac{s}{s^2+1}+\dfrac{1}{s^2+1}.

Taking inverse Laplace transform on both sides of the above, we get

L^{-1}\{\dfrac{2s^2}{(s-1)(s^2+1)}\}=L^{-1}\{\dfrac{1}{s-1}\}+L^{-1}\{\dfrac{s}{s^2+1}+\dfrac{1}{s^2+1}\}\\\\\\\Rightarrow f(x)=e^{1\times x}+\cos (1\times x)+\dfrac{1}{1}\sin(1\times x)\\\\\\\Rightarrow f(x)=e^x+\cos x+\sin x.

Thus, the required answer is

f(x)=e^x+\cos x+\sin x.

4 0
4 years ago
Which of the following is a polynomial?
Rom4ik [11]

Answer:

A. 3x^2+6x is a polynomial

8 0
3 years ago
4(-9x + 1) =<br> Answer?
faltersainse [42]

Answer:

−36+4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How do you solve 3.36/1.4
Leto [7]

Answer:

2.4

Step-by-step explanation:

3 0
3 years ago
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Cole paid $24 for two calculators and one pack of pens. Kai paid $45 for three calculators and two packs of pens. Cole and Kai b
FrozenT [24]

$2.00 more.

gathered info from question:

Kai paid $45

Cole paid $24

It is $6 for each pack of pens

So I did 24- 6 (pack of pens) = 18 (what he used for calculators) and then did  18/2 because he bought two calculators. He paid 9 dollars for each calculator

Kai bought two packs of pens = 12 dollars. 45-12=33, how much he used for the calculators. He bought three calculators so I did 33/3=11. He used 11 dollars for each calculator.

11-9=2.

Kai paid $2.00 more than Cole.



Please mark be brainliest :)



8 0
3 years ago
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