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Eva8 [605]
2 years ago
6

Carla, a nurse in the labor and delivery ward of the hospital, is responsible for measuring the

Mathematics
1 answer:
Sonbull [250]2 years ago
6 0
Answer: 50





Explanation
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ILL GIVE BRAINLEST, Find the value of x.
natali 33 [55]

Answer:

x=6, y=128

 

set 5x+16 = 7x+4

-2x=-12

x=6

plug x into equation= 46

180-46=134

y+6=134

y=128

3 0
3 years ago
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Use conversion factors to find the answer, distance tracked in feet after 12 seconds at 87 miles per hour.
Assoli18 [71]
1 hour=3600 seconds
1 mile=5280 feet
87 miles/hr (1 hr/3600 sec)(5280 ft/mile)=127.6 feet/sec

Distance= Rate*time
d=127.6(12)=1531.2 feet (after 12 seconds) 
3 0
3 years ago
What is a reasonable measure for the angle shown?
dimaraw [331]
I would say 120 since it’s not at the end near 170

4 0
2 years ago
A number is 3 more than 2nd number, the sum of the two numbers is 17. Find the<br> numbers.
Debora [2.8K]
Your numbers are 7 and 10
4 0
2 years ago
A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

D^{2} = (90 - x)^{2} + 90^{2}   (1)

\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}

2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}  

D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}   (2)

Since:

D = \sqrt{(90 -x)^{2} + 90^{2}}

When x = 45 (the batter is halfway to first base), D is:

D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

100.62 \frac{d(D)}{dt} = -(90 - 45)*31          

\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

D^{2} = 90^{2} + x^{2}  

\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}

D\frac{dD}{dt} = x\frac{dx}{dt}   (3)

We have that D is:

D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0
2 years ago
Read 2 more answers
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