first term.
a= 80
second term. a2=10
so Common ratio r=a2/a =10/80=1/8=0.125
checking for the validity of common ratio.
a2×r=10×1/8=10×0.125=1.25 =a3= Third term.
Hence it is true.
Now 4th Term =1.25/8=0.15625
It can be observed that 4TH term Has digit that is 5 places past the decimal point.
Hence, 0.15625 is the terminating number as per the question.
So the required sum is.
S=a+a2+a3+a4
->S=80+10+1.25+0.15625
->S= 91.40625
Hope it helps...
Regards,
Leukonov/Olegion.
Answer:
0
Step-by-step explanation:
Substitute x = 3 into the rational expression
= 
= 
= 0
Answer:C. 17,280
Step-by-step explanation:It this way because it cant be 3k obv or 6k. And it says 72% down not up so not d either :D
Volume
cube and sphere
the diameter of the sphere=height of box=legnth of box=width of box
volume of cube=side^3
volume of sphere=(4/3)pir^3
side=d=2r
Vcube=d^3
vsphere=(4/3)pi(d/2)^3
Vsphere=(pid^3)/6
percent
basketballV/boxV=( (pid^3)/6)/(d^3)=(pid^3)/(6d^3)=pi/3=aprox 0.523599=52.3599% (round if nececary)
