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earnstyle [38]
3 years ago
9

Plz help!!!

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
1.

The tax is normally done to the total so add the prices up  
2.50+8.75+3.00+10.25=24.5
 percent is 6%
 percent means parts out of 100 so
 6%=6/100=0.6/10=0.06/1=0.06* 6% of total* <span>'of'' translates to multiply
</span> 24.50 times 0.06=tax=1.47

2.  (10 * 24) + (2 * 24) = ?

3. Answer is 4
 
4. 
Exact Form:<span>23/2</span>Decimal Form:11.5Mixed Number Form:<span>11<span> 1/2

5.  </span></span><span />p = 40 inches




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lesya692 [45]
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3 0
3 years ago
If y varies directly with x, with k=0.75,what is the value of y when x=12
erma4kov [3.2K]

Answer:

9

Step-by-step explanation:

y=x

y=kx

substitute k for 0.75 and x for 12 in the above equation

y=0.75×12

y=9

7 0
3 years ago
What is the difference between the number 16 and 23
svlad2 [7]

Answer:

Well it’s greater bc 23 is greater than 16

Step-by-step explanation:

I don’t know if u needed this or something else

7 0
3 years ago
Read 2 more answers
A rectangle has a height of k2 + 3 and a width of k2 + 7.
ElenaW [278]

Answer:

The area of the rectangle in polynomial form is k^4 +10 k^2 + 21

Step-by-step explanation:

Given

Shape: Rectangle

Height: k^2 + 3

Width: k^2 + 7

Required

Area of the rectangle

The area of a rectangle is calculated as thus;

Area = Length * Width

By substituting k^2 + 3 for height and k^2 + 7 for width; This gives

Area = (k^2 + 3)(k^2 + 7)

Expand the bracket

Area = k^2(k^2 + 7) + 3(k^2 + 7)

Open each bracket

Area = k^2*k^2 + k^2*7 + 3*k^2 + 3*7

Area = k^4 +7 k^2 + 3k^2 + 21

Area = k^4 +10 k^2 + 21

Hence, the area of the rectangle in polynomial form is k^4 +10 k^2 + 21

5 0
3 years ago
Evaluate the six trigonometric functions of the angle 0<br><br><br><br>is right<br>​
antiseptic1488 [7]

Answer:

1. Sine θ = 1/3

2. Cos θ = 2√2 / 3

3. Tan θ = √2 / 4

4. Cosec θ = 3

5. Sec θ = 3√2 / 4

6. Cot θ = 2√2

Step-by-step explanation:

We'll begin by determining the adjacent. This can be obtained as follow:

Hypothenus (Hypo) = 9

Opposite (Opp) = 3

Adjacent (Adj) =?

Hypo² = Adj² + Opp²

9² = Adj² + 3²

81 = Adj² + 9

81 – 9 = Adj²

72 = Adj²

Take the square root of both side

Adj = √72

Adj = 6√2

Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:

1. Determination of Sine θ

Hypothenus = 9

Opposite = 3

Sine θ =?

Sine θ = Opposite / Hypothenus

Sine θ = 3/9

Sine θ = 1/3

2. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 9

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 9

Cos θ = 2√2 / 3

3. Determination of Tan θ

Opposite = 3

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 3 / 6√2

Tan θ = 1 / 2√2

Rationalise

(1 / 2√2) × (2√2 /2√2)

= 2√2 / 4×2

Tan θ = √2 / 4

4. Determination of Cosec θ

Sine θ = 1/3

Cosec θ =?

Cosec θ = 1 / Sine θ

Cosec θ = 1 ÷ 1/3

Cosec θ = 1 × 3/1

Cosec θ = 3

5. Determination of sec θ

Cos θ = 2√2 / 3

Sec θ =?

Sec θ = 1 / Cos θ

Sec θ = 1 ÷ 2√2 / 3

Sec θ = 1 × 3 / 2√2

Sec θ = 3 / 2√2

Rationalise

= (3 / 2√2) × (2√2 / 2√2)

= 3 × 2√2 / 4×2

Sec θ = 3√2 / 4

6. Determination of Cot θ

Tan θ = √2 / 4

Cot θ =?

Cot θ = 1 / Tan θ

Cot θ = 1 ÷ √2 / 4

Cot θ = 1 × 4 / √2

Cot θ = 4 / √2

Rationalise

= (4 / √2) × (√2 / √2)

= 4√2 / 2

Cot θ = 2√2

8 0
3 years ago
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