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2 years ago

Need help will give brainlist

Mathematics

1 answer:

AnnZ [28]2 years ago

4 0

Answer:

It's the 2nd one 3y2-43y over 12y2

Step-by-step explanation:

First u do a common denominator u multiply on the first side by 6y on the second side by 4 then u solve it till u get 6y2-86y over 24y2 then simplify by dividing by 2

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What is the measure of DHF in circle H? <br> 270<br> 90<br> 220<br> 130

Natalka [10]

Answer: 220

Step-by-step explanation: 130 degrees + the 90 degree angle = 220 degrees

Hope this helps:)

3 0

3 years ago

Value of x in 2x-7=35 is

Reika [66]

Answer:

x=21

Step-by-step explanation:

2x - 7 = 35

+7 +7

-----------------

2x = 42

----- -----

2 2

x = 21

The answer is 21, hope this helps.

4 0

3 years ago

Read 2 more answers

What’s the value of Y?

Montano1993 [528]

Answer:

Step-by-step explanation:

if 88 is the right angle degree, that means the acute angle would be half of 88.

88÷2=44

7 0

3 years ago

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

5 0

3 years ago

When you went to sleep, the temperature was −2.8°C.

galben [10]

The larger the number the warmer it is

7 0

3 years ago

Need help will give brainlist​

Need help will give brainlist