R(s+t) = rs + rt represents Distributive Property because r is multiplying s and t
i.e. ( r*s + r*t )
= rs + rt
So correct answer is Distributive Property.
hope this helps :)
The base area is (pi)(r squared).
Answer:
21.28 and 967.46
Hope it helps have a good night :)))))))))))))))))
She invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.
<h3><u>Distributions</u></h3>
Given that Sylvia invested a total of $27,000, and she invested part of the money in a certificate of deposit (CD) that earns 3% simple interest per year, she invested in a stock that returns the equivalent of 7% simple interest, and she invested in a bond fund that returns 2%, and she invested three times as much in the stock as she did in the CD, and earned a total of $1140 at the end of 1 yr, to determine how much principal did she put in each investment, the following calculation must be made:
- 9000 x 0.07 + 3000 x 0.03 + 15000 x 0.02 = 630 + 90 + 300 = 1020
- 9900 x 0.07 + 3300 x 0.03 + 13800 x 0.02 = 693 + 99 + 276 = 1068
- 12,000 x 0.07 + 4,000 x 0.03 + 11,000 x 0.02 = 840 + 120 + 220 = 1,180
- 11400 x 0.07 + 3800 x 0.03 + 11800 x 0.02 = 798 + 114 + 236 = 1148
- 10800 x 0.07 + 3600 x 0.03 + 12600 x 0.02 = 756 + 108 + 252 = 1116
- 11160 x 0.07 + 3720 x 0.03 + 12120 x 0.02 = 781.2 + 111.6 + 242.4 = 1135.2
- 11190 x 0.07 + 3730 x 0.03 + 12080 x 0.02 = 783.3 + 111.9 + 241.6 = 1136.8
- 11250 x 0.07 + 3750 x 0.03 + 12000 x 0.02 = 787.5 + 112.5 + 240 = 1140
Therefore, she invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.
Learn more about distribution in brainly.com/question/10250387
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C
![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)
LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
