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Monica [59]
3 years ago
11

Use the graph to state the solution for the system.

Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0

Step-by-step explanation:

I. x - y = 4 --> y = x - 4

II. x + y = 4 --> y = 4 - x

Solution is x = 4 and y = 0

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The school purchased baseball equipment and uniforms for a total cost of 1762.00. The equipment costs 598 and the uniforms were
Norma-Jean [14]
U= uniforms


598+ 24.25u= 1762

24.25u= 1762- 598

24.25u= 1164

U= 1164/24.25

U= 48

The school purchased 48 uniforms.

Hope this helps!
3 0
3 years ago
Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the
Sladkaya [172]
7 + (0-7) * 2/3 = 7 - 14/3 = (21 - 14) / 3 = 7/3 = 2.3
5 0
2 years ago
14cm
BabaBlast [244]

Answer:

The answer is 336cm

Step-by-step explanation:

Multiply 24 & 14

6 0
2 years ago
What is not a pair of equivalent fractions for 5/8 and 1/2
n200080 [17]
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18 
15/30: 5/10 OR 1/2 
45/60: 8/12 OR 4/6 

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number. 

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8. 
2/5 and 1/2: 2/5 and 2.5/5 
9/9 and 5/7: 9/9 and ~5.7/9 

Rewrite each in simple form: Find greatest common factor and divide. 

9/54: 1/6 
20/40: 1/2 
100/110: 10/11 

Are these fractions equivalent? 
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole. 


In what situation can you use multiplication to find equivalent fractions? 
I'm sorry but I do not understand this question. 
</span>Source(s):<span>I hope I  helped, seeing as I have graduated with a math degree.</span>
7 0
3 years ago
What is the derivative of w=(t^2+1)^100<br><br> How is it 200t(t^2+1)^99?
GuDViN [60]
(t^2+1)^100

USE CHAIN RULE

Outside first (using power rule)

100*(t^2+1)^99 * derivative of the inside

100(t^2+1)^99 * d(t^2+1)

100(t^2+1)^99 * 2t

200t(t^2+1)^99
6 0
3 years ago
Read 2 more answers
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