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likoan [24]
4 years ago
12

The dimensions of the floor in the family room are 4 meters by 6 meters. 

Mathematics
1 answer:
UkoKoshka [18]4 years ago
5 0
Your answer is b, m squared
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What is the value of i^3?
Pavel [41]

Answer:

the answer is -i

Step-by-step explanation:

4 0
4 years ago
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HELPPPP!!!! The Super Fencing Company builds cedar fences for homes at a cost of
Lina20 [59]

Answer:

16

Step-by-step explanation:

1400/85 = 16.47

largest integer below that is 16

6 0
3 years ago
10 mL = ____________ L ( 1L = 1000 ml
DENIUS [597]

Solution:

<u>Note that:</u>

  • 1 L = 1000 ml

<u>Using the clue above, let's solve each problem.</u>

  • 10 mL        =        10/1,000 L           =           0.01 L
  • 1.2 L          =     1.2 x 1,000 mL        =       1,200 mL
  • 3,500 mL =     3,500/1,000 L        =           3.5 L
  • 4 L            =       4 x 1,000 mL        =       4,000 mL
  • 230 mL    =        230/1,000 L         =           0.23 L
  • 6.21 L       =     6.21 x 1,000 mL      =       6,210 mL

Hoped this helped!

4 0
3 years ago
Simplify 4√16 + 8√16
Mumz [18]

4\sqrt{16} + 8\sqrt{16}:

Since \sqrt{1} =1, we get:

4\cdot \:1\cdot \:6+8\cdot \:1\cdot \:6=24+48=72

-----------------------------------------------------------------------------------

7\sqrt{4} *3\sqrt{8}

We have \sqrt{4}=2

simplify \sqrt{8} = \sqrt{2^3} = \sqrt{2^2*2}

then the radical rule is used: \quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

⇒ \sqrt{2^2*2} = \sqrt{2^2} \sqrt{2}= \sqrt{4}\sqrt{2} =2\sqrt{2}

Now we have \sqrt{4}=2 and \sqrt{8}=2 \sqrt{2}

7\sqrt{4} *3\sqrt{8} = 7*2*3*2\sqrt{2} = 84 \sqrt{2}

-----------------------------------------------------------------------------------

2\sqrt{4}+5 \sqrt{9}

2\sqrt{4} =2*2= 4 and 5\sqrt{9} =5*3= 15

2\sqrt{4}+5 \sqrt{9} = 4+15 = 19

-----------------------------------------------------------------------------------

4\sqrt{5} -2\sqrt{5} = 2\sqrt{5}

since 2\sqrt{5} is the half of 4\sqrt{5}

-----------------------------------------------------------------------------------

-4\sqrt{2}\:+\:5\sqrt{2} =1 \sqrt{2} = \sqrt{2}\\    <em>(-4+5=1)</em>

4 0
3 years ago
Ball B, with a mass of 30kg, is moving to the left at -10 m/s. With what velocity should Ball A, with a mass of 10 kg, move to t
tangare [24]
Initially, Ball A of 10 kg will have velocity x, while Ball B of 30 kg has velocity -10 m/s.
After collision, Ball A will have a velocity of -30 m/s, while Ball B will have velocity 10 m/s. We assume their masses do not change.
(10 kg)(x m/s) + (30 kg)(-10 m/s) = (10 kg)(-30 m/s) + (30 kg)(10 m/s)
10x - 300 = -300 + 300
x = 30 m/s (to the right)
5 0
3 years ago
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