Arrange from smallest to largest
-25, -12/4, 1/5, 18/5, 10
chose the middle number
1/5
U didn’t include the addition sign or sub sign for some of them
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
Answer:
y=-1/5x-16/15
Step-by-step explanation:
slope intercept form y=mx+b
3x+15y=-16
15y=-3x-16 divide both sides by 15
y=-3/15x-16/15 simplify -3/15 to -1/5
y=-1/5x-16/15
Answer:
∠B=60°
Step-by-step explanation:
In this right traingle, using angle B, you have the opposite side which is 6√102, and the adjacent side which is 6√34. Using SOHCAHTOA this invlolves TOA so tangent B = OPPOSITE/ADJACENT or tan B = 6√102/6√34. Simplifying gives tan B=√3. You can use your calculator to solve for B by taking the inverse tangent of √3 or you can use the known trig ratios from the unit circle if you have already learned that to find that angle B is 60°
