6 cm

A bakery uses 3/4 cups of oats to make a 2 4/7 pounds of oatmeal cookies.how many cups of oats are required per pound of cookies

Flura [38]

We can use ratios to find the answer to this.
Set up the ratio.
3/4 / 18/7 = x / 1

Multiply both sides by 1
3/4 / 18/7 = x

Inverse 18/7 to 7/18 so we can multiply.
3/4 * 7/18 = x
Multiply.
21/72 = x
Simplify7/24 = x
Therefore, 7/24 cups of oats is used per pound.

3 0

3 years ago

In it 34/50 of the coins are quarters what percent of the coins are quarters

ziro4ka [17]

Answer:

68% are quarters

Step-by-step explanation:

Percent means out of 100

34/50

Multiply by 2/2

34/50 *2/2

68/100

This means 68 percent

4 0

3 years ago

What is the probability of rolling a number greater than 4 on a number cube and then spinning an

oee [108]

Answer:

1/6

Step-by-step explanation:

There are 2 numbers greater than 4 on a die (5 and 6).

A spinner divided into 12 equal sectors numbered 1 through 12 has 6 even numbered sectors.

Therefore, the probability is:

P = (2/6) (6/12)

P = 1/6

5 0

3 years ago

Alec pours the same amount of soup into three balls he used 4 cups of soup how much soup is in each bowl

Ugo [173]

For this question you would need to do 4 divided by 3. The answer would be 1.3 cup(s) would be in each bowl.

Hope that helps!!

7 0

3 years ago

"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year

KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that $p = 0.56$

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is $P(X \geq 1)$ when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927$

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0

3 years ago