Answer:
a) 4 - 
b) 1 - 
c) 6 - 
Step-by-step explanation:
It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.
We start with:

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

Finally, we divide each side by t^2 to isolate a (answer #6):

Answer:
18:81 12:54
Step-by-step explanation:
Answer:
I think answers is
D
label the x-axis "Pieces of Yarn," and label the y-axis "Length (inches
Answer:
9) slope of AC = slope of FH
Equation of the line is y = - x + 5
10) Area = 320
Step-by-step explanation:
For 9, the only thing similar IS the slope of the hypotenuse because the triangles are along the same line. Unless they're asking for the equation of the line, then that's just using the point slope equation which is:
y = - x + 5
For 10, just multiply 4 and 5 by 4 to get 16 and 20. Then multiply 16 and 20 to get 320.
Answer:
Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.
Step-by-step explanation:
We find the components of the forces in x-y-z
Force of Jack in z =F₁z=90.5 N in direction (+z)
Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)
Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)
Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)
Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)
Calculating of the components of the net force the people exert on the donkey.
Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)
Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)
Fnz =F₁z=90.5 N (+z)
Calculating of the magnitude of the net force the people exert on the donkey.


