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UkoKoshka [18]
3 years ago
8

Solve for x need help asap

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

the answer is 23

Step-by-step explanation:

3x=69 ( vertically opposite angle)

x=69/3

x=23

Hope this helps. :)

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Determine the value of the unknown 374=11(2n+8) ​
IgorLugansk [536]

Answer:

n = 13

Step-by-step explanation:

374 = 11(2n+8) ​

Expand the right side

374 = 11* 2n + 11 * 8

374 = 22n + 88

Subtract 88 from both sides

374 - 88 = 22n

286 = 22n

divide both sides by 22

n = 13

4 0
3 years ago
Read 2 more answers
Maddy found a job with an annual salary of $47.5K. What is her monthly pay, rounded to the nearest dollar?
Deffense [45]
$3,958

explanation:
47,000 / 12 months = 3,958
8 0
2 years ago
Read 2 more answers
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
WARRIOR [948]

Answer:

(a) The probability that more than 180 will take your free sample is 0.1056.

(b) The probability that fewer than 200 will take your free sample is 0.9997.

(c) The probability that a customer will take a free sample and buy the product is 0.2184.

(d) The probability that between 60 and 80 customers will take the free sample and buy the product is 0.8005.

Step-by-step explanation:

We are given that about 56% of all customers will take free samples. Furthermore, of those who take the free samples, about 39% will buy what they have sampled.

The day you were offering free samples, 303 customers passed by your counter.

Firstly, we will check that it is appropriate to use the normal approximation to the binomial, that is;

Is np > 5  and  n(1-p) > 5

In our question, n = sample of customers = 303

                          p = probability that customers will take free sample = 56%

So, np = 303 \times 0.56 = 169.68 > 5

     n(1-p) = 303 \times (1-0.56) = 133.32 > 5

Since, both conditions are satisfied so it is appropriate to use the normal approximation to the binomial.

Now, mean of the normal distribution is given by;

        Mean, \mu = n \times p = 169.68

Also, the standard deviation of the normal distribution is given by;

       Standard deviation, \sigma = \sqrt{n \times p \times (1-p)}

                                            = \sqrt{303 \times 0.56 \times (1-0.56)} = 8.64

Let X = Number of people who will take your free sample

The z score probability distribution for normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

(a) The probability that more than 180 will take your free sample is given by = P(X > 180) = P(X > 180.5)     {Using continuity correction}

        P(X > 180.5) = P( \frac{X-\mu}{\sigma} > \frac{180.5-169.68}{8.64} ) = P(Z > 1.25) = 1 - P(Z < 1.25)

                                                                   = 1 - 0.8944 = <u>0.1056</u>

(b) The probability that fewer than 200 will take your free sample is given by = P(X < 200) = P(X < 199.5)     {Using continuity correction}

        P(X < 199.5) = P( \frac{X-\mu}{\sigma} < \frac{199.5-169.68}{8.64} ) = P(Z < 3.45) = <u>0.9997</u>

(c) We are given in the question that of those who take the free samples, about 39% will buy what they have sampled, this means that we have;

     P(Buy the product / taken a free sample) = 0.39

So, Probability(customer will take a free sample and buy the product) = P(customer take a free sample) \times P(Buy the product / taken a free sample)

     = 0.56 \times 0.39 = <u>0.2184</u>

(d) Now our mean and standard deviation will get changed because the probability of success now is p = 0.2184 but n is same as 303.

So, Mean, \mu = n \times p = 303 \times 0.2184 = 66.18

Standard deviation, \sigma = \sqrt{n \times p \times (1-p)}

                                    = \sqrt{303 \times 0.2184 \times (1-0.2184)} = 7.192

Now, the probability that between 60 and 80 customers will take the free sample and buy the product is given by = P(60 < X < 80) = P(59.5 < X < 80.5)         {Using continuity correction}

     P(59.5 < X < 80.5) = P(X < 80.5) - P(X \leq 59.5)

     P(X < 80.5) = P( \frac{X-\mu}{\sigma} < \frac{80.5-66.18}{7.192} ) = P(Z < 1.99) = 0.9767

     P(X \leq 59.5) = P( \frac{X-\mu}{\sigma} \leq \frac{59.5-66.18}{7.192} ) = P(Z \leq -0.93) = 1 - P(Z < 0.93)

                                                            = 1 - 0.8238 = 0.1762

Therefore, P(59.5 < X < 80.5) = 0.9767- 0.1762 = <u>0.8005.</u>

4 0
3 years ago
Choose an equivalent system of equations to the following system:
andrezito [222]

Answer:

B.  6Fx + 6Gy = 6H

    Qx + Ry = S

Step-by-step explanation:

Equivalent equations can be created many ways. One of the simplest is to multiply both sides of the equation by the same number. In the answer above, the first equation has been multiplied by 6. Nothing has been done to the second equation.

_____

<em>Comments on other choices</em>

A: some terms have been multiplied by 6. This changes the equation(s) so they are no longer equivalent to the ones you started with.

B: the correct choice

C: see A.

D: the first equation has been multiplied by 6, so that is equivalent to the original. The second equation has the sign of one of the terms changed, so it is now a different equation.

3 0
3 years ago
Read 2 more answers
Will give brainliest need anwser now: Karen and Kevin collect coins. Karen has x coins. Kevin has 4 coins fewer than four times
vodka [1.7K]

Answer:

100889999999999999999

5 0
3 years ago
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