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boyakko [2]
3 years ago
14

• 1 hour = 60 minutes

Mathematics
1 answer:
Nataly [62]3 years ago
3 0

1 mile = 1.6 kilometers so 24*1.6 = 38.4
<em>24 miles = 38.4 kilometers</em>

1 kilometer = 1000 meters so 38.4*1000 = 38,400 meters
<em>38.4 kilometers = 38,400 meters

</em>1 hour = 60 minutes so 2*60 = 120
<em>2 hours = 120 minutes
</em>
To calculate meters per minute, divide.
38,400 / 120 = 320

So that means that Calvin's approximate speed is 320 meters per minute.

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what is an equation in point-slope form for the line that passes through the points (1,-2) and has a slope of 3
VMariaS [17]

Answer:

y=3x-5

Step-by-step explanation:

5 0
4 years ago
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Samuel is 5/8 inch taller than Jackie, Shelly is 0.7 inch taller than Jackie, Craig is 1/2 inch taller than Jackie, who is the t
miskamm [114]
If you would like to know who is the tallest, you can calculate this using the following steps:

Jackie ... j
Samuel: 5/8 inch + j = 5/8 + j = 0.625 + j
Shelly: 0.7 inch + j = 0.7 + j
Craig: 1/2 inch + j = 1/2 + j = 0.5 + j

The correct result would be: Shelly is the tallest.
8 0
3 years ago
Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.
lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55

5 0
3 years ago
The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2
gtnhenbr [62]

Answer:

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

Step-by-step explanation:

d²y/dx² = (-2y² − x²) / (4y³)

Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)

d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)

Substitute:

d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)

d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

8 0
4 years ago
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A square is drawn below what is the value of x
Andru [333]

Answer:

You donf have the picture shown, how is anybody supposed to work on it

3 0
3 years ago
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