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3 years ago

If f(x) = 8x2 + 4x - 12. Find f(2) f(2)=

Mathematics

1 answer:

posledela3 years ago

3 0

Answer:

f(2) = 28

Step-by-step explanation:

$\rm f(x) = 8 {x}^{2} + 4x - 12$

$\rm Evaluate \: 8 x^2 + 4 x - 12 \: where \: x = 2: \\ \\ \rm \implies f(2) = 8 \times {2}^{2} + 4 \times 2 - 12 \\ \\ \rm \implies f(2) = 8 \times 4 + 8 - 12 \\ \\ \rm \implies f(2) = 32 - 4 \\ \\ \rm \implies f(2) = 28$

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One number exceeds another by -1. the sum of the numbers is 5. what are the numbers?

maks197457 [2]

X-y=-1
x+y=5
y=x+1
x+x+1=5
2x+1=5
2x=4
x=2
y=x+1
y=2+1
y=3

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3 years ago

Rudy is 6 feet 6 inches tall, weighs 210 pounds, and is very muscular. if you think that rudy is more likely to be a basketball

madam [21]

The answer is representativeness heuristic. This is used when making decisions about the likelihood of an occasion under doubt. It is unique of a group of heuristics (simple rules leading decision or decision-making) suggested by psychologists Amos Tversky and Daniel Kahneman in the 1970s.

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3 years ago

At the start of 2014, tim house was worth £100,000 the value of the house increases by 10%per every year work out the value of h

kotykmax [81]

Answer:

$146410

Step-by-step explanation:

The formula for calculating future value:

FV = P (1 + r)^n

FV = Future value

P = Present value

R = interest rate

N = number of years

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3 years ago

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9

Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that $\mu = 8.9, \sigma = 2.9$

Sample of 37:

This means that $n = 37, s = \frac{2.9}{\sqrt{37}}$

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -0.53$

$Z = -0.53$ has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -3.08$

$Z = -3.08$ has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

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3 years ago

using whole numbers, fractions, and decimals, write at least eight addition equations that have the sum of 10

LuckyWell [14K]

<span>Using whole numbers, fractions, and decimals, these are the eight addition equations that have the sum of 10
</span>1. 5+5=10
2. 1 1/2 + 8 1/2 =10
3. 2.9+7.1=10
4. 6 1/3 + 3 2/3 =10
5. 4 3/5 + 5 2/5=10
6. 9.01+.99=10
7. 3.72+6.28 = 10
8. 8 8/9+ 1 1/9=10

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4 years ago