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2 years ago

Anyone can answer this ?

Mathematics

1 answer:

TEA [102]2 years ago

7 0

Answer:

NOT nets = A, C, D, F
Nets = B, E, G, H

Figure B (Triangular prism)

SA: 3 rectangles + 2 triangles

Rectangles: (20·8) + (20·10) + (20·6) = 480 ft²

Triangles: (8·6)/2 + (8·6)/2 = 48 ft²

Total SA: 528 ft²

Figure E (Square pyramid)

SA: 1 square + 4 triangles

Square: 10·10 = 100 yd²
Triangles: (12·10)/2 + (12·10)/2 + (12·10)/2 + (12·10)/2 = 240 yd²

Total SA: 340 yd²

Figure G (Rectangular prism)

SA = 2 wide rectangles + 4 narrow rectangles

Wide: (7·11) + (7·11) = 154 cm²

Narrow: (2·7) + (2·7) + (11·3) + (11·3) = 94 cm²

Total SA: 248 cm²

Figure H (Cube)

SA = 6 squares

Squares: 6 x (1·1) = 6 m²

Total SA: 6 m²

I hope this helps and God bless!

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1 year ago

Show Work Please Thank You

Misha Larkins [42]

Answer:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

Step-by-step explanation:

We are given the trigonometric equation of:

$\displaystyle{\sin 4x = \dfrac{\sqrt{3}}{2}}$

Let u = 4x then:

$\displaystyle{\sin u = \dfrac{\sqrt{3}}{2}}\\\\\displaystyle{\arcsin (\sin u) = \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}\\\\\displaystyle{u= \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}$

Find a measurement that makes sin(u) = √3/2 true within [0, π) which are u = 60° (π/3) and u = 120° (2π/3).

$\displaystyle{u = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Convert u-term back to 4x:

$\displaystyle{4x = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

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1 year ago

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