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Allisa [31]
3 years ago
10

Halie is a perfectionist and wants each piece of her cake to be exactly the same area. if the diameter of her cake is 12 in and

she wants to cut it into 8 pieces, what is the area of each piece of cake? round to the nearest tenth.
Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0
To find this answer you need to find the area of the whole cake and divide it by 8. To find area of a circle, you need the formula (pi)*r^2. The radius is the diameter divided by two. Your final formula would be (pi)*8^2. This is approx. 201.06 in^2. Divide this number by 8, and you have your answer. I got 25.13 in^2.
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Nikki bought a patio set on sale for $480. The original price was $850. What was the rate of discount?
ASHA 777 [7]

Answer:

43.5 % decrease

Step-by-step explanation:

Take the original price and subtract the new price

850-480

370

Divide by the original price

370/850

.435294118

Change to percent form by multiplying by 100

43.5294118 % decrease

43.5 % decrease

3 0
3 years ago
11/6358 long agurithum
miss Akunina [59]

Answer:

Least common multiple:

lcm (578; 11) = 6,358 = 2 × 11 × 172;

Numbers have no common prime factors: 6,358 = 578 × 11.

Step-by-step explanation:

Approach 1. Integer numbers prime factorization:

578 = 2 × 172;

11 is a prime number, it cannot be broken down to other prime factors;

Multiply all the prime factors, by the largest exponents.

Least common multiple:

lcm (578; 11) = 2 × 11 × 172;

lcm (578; 11) = 2 × 11 × 172 = 6,358

Numbers have no common prime factors: 6,358 = 578 × 11.

Integer numbers prime factorization

Approach 2. Euclid's algorithm:

Calculate the greatest (highest) common factor (divisor), gcf, hcf, gcd:

Step 1. Divide the larger number by the smaller one:

578 ÷ 11 = 52 + 6; Step 2. Divide the smaller number by the above operation's remainder:

11 ÷ 6 = 1 + 5; Step 3. Divide the remainder from the step 1 by the remainder from the step 2:

6 ÷ 5 = 1 + 1; Step 4. Divide the remainder from the step 2 by the remainder from the step 3:

5 ÷ 1 = 5 + 0; At this step, the remainder is zero, so we stop:

1 is the number we were looking for, the last remainder that is not zero.

This is the greatest common factor (divisor).

Least common multiple, formula:

lcm (a; b) = (a × b) / gcf, hcf, gcd (a; b);

lcm (578; 11) =

(578 × 11) / gcf, hcf, gcd (578; 11) =

6,358 / 1 =

6,358;

lcm (578; 11) = 6,358 = 2 × 11 × 172;

8 0
3 years ago
1) 1:6 - 20:24<br>2) 44: 72 = x: 36<br>3) 3:4 = 12:f​
otez555 [7]
X=44x36/72
X=22

f=12x4/3
f=16
7 0
3 years ago
Solve the equation for y. Type out your steps to solve this problem as you are showing your work:
Nadya [2.5K]

Answer:

-13/2

Step-by-step explanation:

7(y+3)=5y+8

7y+21=5y+8

7y-5y+21=8

2y+21=8

2y=8-21

2y=-13

y=-13/2

8 0
3 years ago
Read 2 more answers
In 4 years, your son will be entering college and you would like to help financially. You decide to create a college fund and ma
avanturin [10]
The formula you can use for the withdrawals is that of an annuity. You have interest adding to the balance at the same time withdrawals are reducing the balance.

The formula I remember for annuities is
.. A = Pi/(1 -(1 +i)^-n) . . . . . i is the interest for each of the n intervals; A is the withdrawal, P is the initial balance.
This formula works when the withdrawal is at the end of the interval. To find the principal amount required at the time of the first withdrawal, we will compute for 3 withdrawals and then add the 7500 amount of the first withdrawal.
.. 7500 = P*.036/(1 -1.036^-3)
.. 7500 = P*0.357616
.. 7500/0.0347616 = P = 20,972.20
so the college fund balance in 4 years needs to be
.. 20,972.20 +7,500 = 28,472.20

Since the last payment P into the college fund earns interest, its value at the time of the first withdrawal is P*1.036. Each deposit before that earns a year's interest, so the balance in the fund after 4 deposits is
.. B = P*1.036*(1.036^4 -1)/(1.036 -1)
We want this balance to be the above amount, so the deposit (P) is
.. 28,472.20*0.036/(1.036*(1.036^4 -1)) = 6510.62

You must make 4 annual deposits of $6,510.62 starting now.
5 0
3 years ago
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