The volume given is 3Pi(x^3) and the radius is x.
The formula for the volume of a cone is V= [1/3]Pi(r^2)*height
=> [1/3]Pi (r^2) x = 3Pi(x^3) =>
(r^2)x = 3*3(x^3) => (r^2)x = 9(x^3) => (r^2) = 9x^2 =>
r = sqrt[9x^2] = 3x.
<span>Answer: r = 3x</span>
Answer:
x≈1.53182607
Step-by-step explanation:
m athw a y
Answer:
2 pints. it costs the same and you get more
Begin with cos(θ) = 5/13, θ in Quadrant IV
you should distinguish the 5-12-13 right-angled triangle
and then cosØ = adjacent/hypotenuse
x = 5, r = 13 , y = -12, since Ø is in IV
and sinØ = -12/13
also tan(ϕ) = −√15 = -√15/1 = y/x and ϕ is in II,
y = √15 , x = -1
r^2 = x^2 + y^2 = 15+1 = 16
r = 4
sinϕ = √15/4 , cosϕ = -1/4
you must know that:
cos(θ − ϕ) = cosθcosϕ + sinθsinϕ
= (5/13)(-1/4) + (-12/13)(√15/4)
= -5/52 - 12√15/52
= (-5-12√15)/52