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astraxan [27]
2 years ago
11

Also may i have help with this one

Mathematics
1 answer:
mote1985 [20]2 years ago
4 0
The answer should be 11 since adding all the x’s up before 13 equals 11
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The relation {(-1, 4), (2, 7), (3, 7)} is a function. True False
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Is it possible to draw a rectangle that has 24 units and a perimeter of 24 units
Marizza181 [45]
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4 0
3 years ago
Please help I will give brainliest to the right answer!!!
timama [110]

Answer:

Step-by-step explanation:

Given function l:

h= -16t² + 26t

where h represents height and t represents time.

The time for dolphin atbthe height 5 feet is given by putting the value of h as 5 in the function,

5 = -16t² + 26t

16t² - 26t + 5 = 0

For this equation: a=16, b=-26, c=5

Use quadratic formula with a=16, b=-26, c=5.

x=(−b±√b2−4ac)/2a

x=−(−26)±√(−26)2−4(16)(5)/2(16)

x=13/16 + 1/16√89 or x=13/16+ −1/16√89

x=1.40 or 0.22

5 0
3 years ago
I’m unsure of what this is. help someone
JulsSmile [24]
<h2>Part 1)</h2>

Let's analyze each part of the function:

FROM x = 0 TO x = 5:

We can find the equation of this line by using The Slope-Intercept Form of the Equation of a Line, that states:

The \ graph \ of \ the \ equation: \\ \\ y=mx+b \\ \\ is \ a \ line \ whose \ slope \ is \ m \ and \ whose \ y-intercept \ is \ (0, b)

So the y-intercept here is (0,4) and m=\frac{4}{5}, therefore:

\boxed{y=\frac{4}{5}x+4}

FROM x = 0 TO x = 5:

From the previous line, we know that at x=5 the output is:

y=\frac{4}{5}x+4 \\ \\ y=\frac{4}{5}(5)+4 \\ \\ y=4+4=8

So the point P_{1}(5,8) lies on both lines.

For this new line, the slope is m=-\frac{3}{5}

So, with the Point-Slope Form of the Equation of a Line we can find the equation of this other line:

The \ equation \ of \ the \ line \ with \ slope \ m \\ passing \ through \ the \ point \ (x_{1},y_{1}) \ is:\\ \\ y-y_{1}=m(x-x_{1})

So:

y-8=-\frac{3}{5}(x-5) \\ \\ y=8-\frac{3}{5}x+3 \\ \\ \boxed{y=-\frac{3}{5}x+11}

The graph is shown below.

<h2>Part 2)</h2>

The graph of the linear function f(x)=ax+b is a line with slope m=a and y-intercept at (0,b). From the items, we can assure that the following equations are linear functions:

\bullet 3y=2x-1.5 \ because \ y=\frac{2}{3}x-\frac{1}{2} \\ \\ \\ \bullet y=1 \ because \ y=m(0)+1 \\ \\ \\ \bullet 5(x+y)=-25 \ because \ 5x+5y=-25 \ \therefore 5y=-5x-25 \therefore y=-x-5

In conclusion, the other functions are nonlinear and they are:

\bullet \ y=x^2+3 \\ \\ \bullet \ y=x^3 \\ \\ \bullet \ y=12-x^2

7 0
3 years ago
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