1 year ago

Also may i have help with this one

Mathematics

1 answer:

mote1985 [20]1 year ago

4 0

The answer should be 11 since adding all the x’s up before 13 equals 11

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An experiment involves selecting a random sample of 256 middle managers for study. One item of interest is their annual incomes.

lesantik [10]

Answer:

the standard error is 153.125

Step-by-step explanation:

given that

The random sample is 256

The sample mean is $35,420

And, the standard deviation is $2,450

We need to find out the standard error

We know that

= standard deviation ÷ √random sample

= 2450 ÷ √256

= 2450 ÷ 16

= 153.125

Hence, the standard error is 153.125

7 0

2 years ago

Simplify (xy)^-3/(x^-5y)^3

Nesterboy [21]

$Use:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\a^n:a^m=a^{n-m}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^{-n}=\left(\frac{1}{a}\right)^{n}\\==================================\\\frac{(xy)^{-3}}{(x^{-5}y)^3}=\frac{x^{-3}y^{-3}}{(x^{-5})^3y^3}=\frac{x^{-3}y^{-3}}{x^{-15}y^3}=x^{-3-(-15)}y^{-3-3}=\boxed{x^{12}y^{-6}=\frac{x^{12}}{y^6}}$