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jonny [76]
2 years ago
13

Find the midpoint M of the line segment joining the points P = (4, 2) and Q = (-6, -8)

Mathematics
2 answers:
const2013 [10]2 years ago
4 0

Answer:

(- 1, - 3 )

Step-by-step explanation:

the coordinates of the midpoint are the average of the coordinates of the endpoints, then

midpoint = (\frac{4-6}{2}, \frac{2-8}{2} ) = ( \frac{-2}{2}, \frac{-6}{2} ) = (- 1, - 3 )

stich3 [128]2 years ago
3 0
(Sum of x coordinates divided by 2,sum of y coordinates divided by 2)
(4+-6/2 , 2+-8/2)
(-2/2,-6/2)
(-1,-3) =M
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3 years ago
In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat
monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

f(t) = 10000(0.9407)^t

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

f(t) = f(0)(1-r)^t

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that f(0) = 10000, thus:

f(t) = 10000(1-r)^t

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

f(2) = 8850

We use this to find 1 - r.

f(t) = 10000(1-r)^t

8850 = 10000(1-r)^2

(1-r)^2 = \frac{8850}{10000}

(1-r)^2 = 0.885

\sqrt{(1-r)^2} = \sqrt{0.885}

1 - r = 0.9407

Thus

f(t) = 10000(1-r)^t

f(t) = 10000(0.9407)^t

7 0
3 years ago
A line is reflected. Which of these could be the result? Pls help
Arte-miy333 [17]

Answer:

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Step-by-step explanation:

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In the coordinate plane, choose the graph with the conditions given.<br><br> x = -3
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You have not given any graphs to choose from but x=-3 would be the graph that has a vertical line running through every point that has -3 as an x coordinate and would cross the x axis (the horizontal axis) at -3

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3 years ago
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Svetlanka [38]
The horizontal beams are what I like to think of as "rail road tracks". The metal portion of the tracks anyway. Notice how angle 2 and angle 8 are inside the tracks, so we consider them "interior angles"

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