Please help mee get the answer today

If a plane flies 612 km per hour, approximately how many kilometres will it travel in 13 hours?

zaharov [31]

$612km...........1h \\ x...................13h \\ \\ x=\frac{612*13}{1} \\ \\ \boxed{x=7956km}$

7 0

3 years ago

Read 2 more answers

HEEEEELLLLPPPP

Karolina [17]

Answer:

Finding the distance between two distinct points on a plane is the same as finding the hypotenuse of a right triangle. From this perspective, the distance formula states that the distance of two distinct points on a plane is equal to the square root of the sum of the square of the rise and run.

I can not Put Out The Points So Im sorry.

3 0

3 years ago

What is the answer to 9+3/4x=7/8x-10

kolezko [41]

$9+ \frac{3}{4} x = \frac{7}{8} x-10 \ \ \ \ \ /\cdot8 \\ 72+6x=7x-80 \\ -x=-152 \\ x=152$

4 0

3 years ago

A circle k(O) with radius 4.5 cm is given. Through point A (OA=9 cm) draw two tangents to the circle. What is the measure of the

Alexxx [7]

Answer:

60°

Step-by-step explanation:

A tangent, together with a radius to the tangent point and segment OA, forms a right triangle with hypotenuse 9 and opposite side 4.5. SOH CAH TOA reminds you that the sine of an agle is the ratio of the opposite side to the hypotenuse of the right triangle.

Thus half the angle at A is the angle whose sine is 4.5/9 = 1/2. That angle is 30°, so the entire angle between the tangents at A is 2·30° = 60°.

6 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of at the same time that water is being pumped into the tank at a con

Alexus [3.1K]

Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank

<h3>Answer:</h3>

The rate at which water is being pumped into the tank is 289,752 $cm^3/min$

<h3>Solution:</h3>

According to question,

There is an inverted conical tank, through which water is leaking at a rate of 10,500 cm3/min at the same time that water is being pumped into the tank at a constant rate

The dimension of tank are:

Diameter = 4cm

Radius(r) = $\frac{diameter}{2}$ = 2cm

Height = 6cm

Clearly we can see that height is 3 times radius so, we can write

h = 3r OR r = h/3 ……………………. (1)

The volume of cone "V" is given as:

$\text { volume of cone }(\mathrm{V})=\frac{1}{3} \pi r^{2} h$ -------- (2)

From (1) and (2)

$\text { Volume of cone(V) }=\frac{1}{3} \pi\left(\frac{h}{3}\right)^{2} h$

$\mathrm{V}=\frac{\pi h^{3}}{27}$ -------- (3)

Now we calculate the derivate:-

$\frac{d V}{d t}=\frac{3 \pi h^{2}}{27} \frac{d h}{d t}$

$\frac{d V}{d t}=\frac{\pi h^{2}}{9} \frac{d h}{d t}$ --------- (4)

According to question, when height is 2m = 200cm, the water level is rising at a rate of 20 cm/min

$\frac{d h}{d t}=20 \mathrm{cm} / \mathrm{min}$

On putting above values in equation(4) and solving we get

$\frac{d V}{d t}=279252$

Hence, the rate at which water is being pumped is 289,752 $cm^3/min$ which is the sum of water volume increasing at rate of 279,252 and 10,500 leaking out

3 0

3 years ago