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2 years ago

Can anyone please help answer this?

Mathematics

1 answer:

Grace [21]2 years ago

8 0

A = 45 inches!

11 + 7 = 18

12 + 5 = 17

6 + 4 = 10

18 + 17 = 35

35 + 10 = 45

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Assume that the random variable X is normally distributed with mean μ=80 and standard deviation σ=18. Find the 11th percentile f

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3 years ago

to convert measurements in the metric system you can move the decimal point left or right why does this work?

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3 years ago

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Bobby catches 8 passes in 3 football games. At this rate how many passes dose he catch in 15 games?expine

stepan [7]

Answer: 40

Step-by-step explanation:

I can see the answer is 40, but let's try to figure out how to do it.

I like to use the rule of 3. Let's put the number of passes on the left side and the number of games on the right side.

$\frac{8}{x}=\frac{3}{15}$

''x'' represents the number of passes in 15 games.

Solve for x;

$x=\frac{15*8}{3}\\ x=\frac{120}{3}\\ x=40$

8 0

3 years ago

Solve the right triangle, ΔABC, for all the missing side and angles to the nearest tenth given sides a = 10.6 and b = 19.2.

Aliun [14]

Answer:

Part 1) $c=21.9\ units$

Part 2) $B=61.1\°$

Part 3) $A=28.9\°$

Part 4) $C=90\°$

Step-by-step explanation:

step 1

Find the length side c

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

substitute the given values

$c^{2}=10.6^{2}+19.2^{2}$

$c^{2}=481$

$c=21.9\ units$

step 2

Fin the measure of angle B

we know that

In the right triangle

$tan(B)=b/a$

substitute the given values

$tan(B)=19.2/10.6$

$B=arctan(19.2/10.6)=61.1\°$

step 3

Find the measure of angle A

we know that

The measure of interior angles in a triangle must be equal to 180 degrees

∠A+∠B+∠C=180°

Remember that in a right triangle the measure of angle C is 90 degrees

we have

$B=61.1\°$

$C=90\°$

substitute

$A+61.1\°+90\°=180\°$

$A=28.9\°$

4 0

3 years ago

Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.

Ratling [72]

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

(3,4)

(4,-6)

The distance 'd' between (3,4) and (4,-6)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):$

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

substituting the points values

$=\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}$

$=\sqrt{1+10^2}$

$=\sqrt{1+100}$

$=\sqrt{101}$

$=10.0$ units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

4 0

3 years ago