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Bas_tet [7]
3 years ago
7

What is the most precise classification of the quadrilateral formed by connecting the midpoints of the sides of a square?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0
A square again
Lets take a is side of a square.
if u take parts of square from mid point and measure distance or length of any sides that would be a/2

then use Pythagorean theorem to solve hypotenuse u will get all length of small quadrilateral a/√2.same for all sides.
I see that will be square again
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Which equation has the same solution as w / 3.9 = 3? A. w+0.6=1.9 B. w-0.6 = 11.1 C. w+1.03=2.93 D. w-1.03=8.24
cestrela7 [59]

The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Given:

w / 3.9 = 3

cross multiply

w × 3 = 3.9

3w = 3.9

divide both sides by 3

w = 3.9 / 3

w = 1.3

<em>Check all that applies</em>

A. w+0.6=1.9

w = 1.9 - 0.6

w = 1.3

B. w-0.6 = 11.1

w = 11.1 + 0.6

w = 11.7

C. w+1.03=2.93

w = 2.93 - 1.03

w = 1.9

D. w-1.03=8.24

w = 8.24 + 1.03

w = 9.27

Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Learn more about equation:

brainly.com/question/2972832

6 0
2 years ago
15 meters to yards (to the nearest hundredth
Usimov [2.4K]

16.4041995 rounding that would be 16 rounding to the nearest hundredth would be 16.400 (or 16.4) yards.

7 0
3 years ago
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Perform the indicated operation.<br> xyz times 1/xyz<br><br> A. 0 <br> B. x^2y^2z^2 <br> C. 1
Irina18 [472]
We have to perform the indicated operation.
x y z times 1 / x y z:
x y z * 1 / x y z = (x y z) / (x y z) = 1
Answer:
C ) 1
3 0
3 years ago
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The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is
anastassius [24]

Answer:

The rate of change of temperature is 1.29 degree Celsius per second.  

Step-by-step explanation:

We are given the following information in the question:

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius where x and y are measured in centimeters.

x = \sqrt{2+t}\\\\y = 5 + \displaystyle\frac{1}{14}t

T_x(4,6) = 8, T_y(4,6) = 4

We have to find the rate at which the temperature is rising on the bug's path after 14 seconds.

At t = 14 seconds, we have,

x = \sqrt{2+14} = 4\\\\y = 5 + \displaystyle\frac{1}{14}(14) = 5+1 = 6

To find rate of change of temperature, we differentiate,

\displaystyle\frac{dT}{dt} = \frac{dT}{dx}\frac{dx}{dt} + \frac{dT}{dy}\frac{dy}{dt}\\\\\displaystyle\frac{dT}{dt} = T_x(x,y)(\frac{1}{2\sqrt{2+t}}) + T_y(x,y)\frac{1}{14}\\\\At~ t = 14, x = 4, y = 6\\\\\frac{dT}{dt} = T_x(4,6)(\frac{1}{2\sqrt{2+t}}) + T_y(4,6)\frac{1}{14}\\\\\frac{dT}{dt} = 8\times \frac{1}{8} +4\times \frac{1}{14} = 1 + 0.2857 = 1.2857

Thus, the rate of change of temperature is 1.29 degree Celsius per second.

7 0
3 years ago
Explain the diffrent between (-5)^2 and -5^2
goldfiish [28.3K]

Answer:

Step-by-step explanation:

The difference would be that for (-5)^2 you would have to do anything that was in the parenthesis first and then square it up, but for -5^2 you would just square it up immediately. In this specific case both outcomes would be the same result and the answer would be 25 since a negative times a negative is a positive. It would be the same because there is nothing in the parenthesis.

7 0
3 years ago
Read 2 more answers
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